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Mashutka [201]
3 years ago
12

Which best describes the complement of spinning any number less than 3?

Mathematics
1 answer:
tatuchka [14]3 years ago
8 0

Answer:

  • <u>The complement of spinning any number less than 3, is spinning a number equal to or greater than 3.</u>

Explanation:

The complement of a subset is the subset of elements that are not in the given subset.

You must know which numbers the spinner has.

Assuming the spinner has the numbers 1, 2, 3, 4, the complement of spinning any number less than 3, is spinning a number that is not less than 3.

Then, that is spinning a number that is equal to or greater than 3.

The numbers that are equal to  or greater than four, for a spinner that has the numbers 1, 2, 3, and 4 are 3 and 4.

Thus, the complement of spinning any number less than 3 is spinning a three or a four.

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Step-by-step explanation:

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Answer is C have a nice day
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3 years ago
Math help please =)
a_sh-v [17]
2x - 3 < 11 or 8x -10 < 82:  <span>X < 23/2
<span>
Part 1</span>
</span>2x-3<11
Add 3 both sides
2x-3+3<11+3
Refine
2x<14
Divide by 2 on both sides
2x / 2    /   14 / 2
Refine
x < 7
<span>
Part 2</span>
8x-10<82
Add 10 to both sides
8x-10+10<82+10
Refine
8x<92
Divide by 8
8x / 8   /   92 / 8
Refine
x < 23 / 2
7 0
3 years ago
A survey of 1,562 randomly selected adults showed that 522 of them have heard of a new electronic reader. The accompanying techn
tester [92]

Answer:

a) We want to test the claim that 35​% of adults have heard of the new electronic reader, then the system of hypothesis are.:  

Null hypothesis:p=0.35  

Alternative hypothesis:p \neq 0.35  

And is a two tailed test

b) z=\frac{0.334 -0.35}{\sqrt{\frac{0.35(1-0.35)}{1562}}}=-1.326  

c) p_v =2*P(z  

d) Null hypothesis:p=0.35  

e) Fail to reject the null hypothesis because the P-value is greater than the significance level, alpha.

Step-by-step explanation:

Information provided

n=1562 represent the random sample selected

X=522 represent the people who have heard of a new electronic reader

\hat p=\frac{522}{1562}=0.334 estimated proportion of people who have heard of a new electronic reader

p_o=0.35 is the value to verify

\alpha=0.05 represent the significance level

z would represent the statistic

p_v represent the p value

Part a

We want to test the claim that 35​% of adults have heard of the new electronic reader, then the system of hypothesis are.:  

Null hypothesis:p=0.35  

Alternative hypothesis:p \neq 0.35  

And is a two tailed test

Part b

The statistic for this case is given :

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

Replacing the info given we got:

z=\frac{0.334 -0.35}{\sqrt{\frac{0.35(1-0.35)}{1562}}}=-1.326  

Part c

We can calculate the p value using the laternative hypothesis with the following probability:

p_v =2*P(z  

Part d

The null hypothesis for this case would be:

Null hypothesis:p=0.35  

Part e

The best conclusion for this case would be:

Fail to reject the null hypothesis because the P-value is greater than the significance level, alpha.

5 0
3 years ago
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