WILL MARK BRAINLEIST!! name all segments skew to bc
2 answers:
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<span>The complete question is shown in the attached image
<u><em>Answer:</em></u>
measure angle H = 42</span>°<span>
<u><em>Explanation:</em></u>
<u>There is a theorem that states that:</u>
"In a triangle, the measure of the exterior angle is equal to the sum of the measures of the two non-adjacent angles to the exterior angle"
<u>In the given, we have:</u>
angle E is an exterior angle to triangle DFH
The two non-adjacent angles to angle E are angles D and H
<u>Based on the above rule:</u>
measure angle E = measure angle D + measure angle H
<u>We are given that:</u>
angle E = 87</span>°<span>
angle D = 45</span>°<span>
<u>Substitute with the givens in the above rule and solve for the measure of angle H as follows:</u>
angle E = angle D + angle H
87</span>°<span> = 45</span>°<span> + measure angle H
measure angle H = 87</span>°<span> - 45</span>°<span>
measure angle H = 42</span>°<span>
Hope this helps :)</span>
<u><em>Answer:</em></u>
measure angle H = 42</span>°<span>
<u><em>Explanation:</em></u>
<u>There is a theorem that states that:</u>
"In a triangle, the measure of the exterior angle is equal to the sum of the measures of the two non-adjacent angles to the exterior angle"
<u>In the given, we have:</u>
angle E is an exterior angle to triangle DFH
The two non-adjacent angles to angle E are angles D and H
<u>Based on the above rule:</u>
measure angle E = measure angle D + measure angle H
<u>We are given that:</u>
angle E = 87</span>°<span>
angle D = 45</span>°<span>
<u>Substitute with the givens in the above rule and solve for the measure of angle H as follows:</u>
angle E = angle D + angle H
87</span>°<span> = 45</span>°<span> + measure angle H
measure angle H = 87</span>°<span> - 45</span>°<span>
measure angle H = 42</span>°<span>
Hope this helps :)</span>
Inequation 1:
to plot the pairs (x, y) for which the inequation holds, draw the line
then pick a point in either side of the line. If that point is a solution of the inequation, than color that region of the line, if that point is not a solution, then color the other part of the line.
we do the same for the second inequation. Then the solution, is the region of the x-y axes colored in both cases.
inequation 2:
draw the lines
i) use points (0, -3), (3, -1)
ii)
use points ( 0, 4), (3, 2)
let's use the point P(3, 3) to see what region of the lines need to be coloured:
;
, not true so we color the region not containing this point
not true, so we color the region not containing the point (3, 3)
The graph representing the system of inequalities is the region colored both red and blue, with the blue line not dashed, and the red line dashed.
to plot the pairs (x, y) for which the inequation holds, draw the line
then pick a point in either side of the line. If that point is a solution of the inequation, than color that region of the line, if that point is not a solution, then color the other part of the line.
we do the same for the second inequation. Then the solution, is the region of the x-y axes colored in both cases.
inequation 2:
draw the lines
i)
ii)
let's use the point P(3, 3) to see what region of the lines need to be coloured:
The graph representing the system of inequalities is the region colored both red and blue, with the blue line not dashed, and the red line dashed.