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Naya [18.7K]
3 years ago
14

Which fractions are equivalent to 40%? Check all that apply.

Mathematics
2 answers:
NNADVOKAT [17]3 years ago
5 0
4 over 10, 8 over 20, and Two-fifths.
Aleksandr [31]3 years ago
5 0

Answer:

2/5

8/20

4/10

16/40

Step-by-step explanation:

hope this helps :)

if this helps pls mark me as brainliest:)

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I need help please and thanks
Akimi4 [234]
Perimeter of rectangle = all sides added
= 3+3+7+7 =20


volume of sphere = 4/3 x π x r(cubed)
= 4/3 x π X 4(cubed)
= 268.08257

area of triangle = base x height / 2
= 5 x 6 / 2
=30/2 =15

volume of pyramid = base height x base width x height / 3
= 300

side of triangle ---> use Pythagoras theorem so a(squared) + b (squared) = c(squared)
4(squared) + 3(squared) = c(squared)
16 + 9 = c(squared)
25 = c(squared)
c = 5


yw sis xoxoxo





7 0
2 years ago
EXAMPLE 5 Find the maximum value of the function f(x, y, z) = x + 2y + 11z on the curve of intersection of the plane x − y + z =
Taya2010 [7]

Answer:

\displaystyle x= -\frac{10}{\sqrt{269}}\\\\\displaystyle y= \frac{13}{\sqrt{269}}\\\\\displaystyle z = \frac{23\sqrt{269}+269}{269}

<em>Maximum value of f=2.41</em>

Step-by-step explanation:

<u>Lagrange Multipliers</u>

It's a method to optimize (maximize or minimize) functions of more than one variable subject to equality restrictions.

Given a function of three variables f(x,y,z) and a restriction in the form of an equality g(x,y,z)=0, then we are interested in finding the values of x,y,z where both gradients are parallel, i.e.

\bigtriangledown  f=\lambda \bigtriangledown  g

for some scalar \lambda called the Lagrange multiplier.

For more than one restriction, say g(x,y,z)=0 and h(x,y,z)=0, the Lagrange condition is

\bigtriangledown  f=\lambda \bigtriangledown  g+\mu \bigtriangledown  h

The gradient of f is

\bigtriangledown  f=

Considering each variable as independent we have three equations right from the Lagrange condition, plus one for each restriction, to form a 5x5 system of equations in x,y,z,\lambda,\mu.

We have

f(x, y, z) = x + 2y + 11z\\g(x, y, z) = x - y + z -1=0\\h(x, y, z) = x^2 + y^2 -1= 0

Let's compute the partial derivatives

f_x=1\ ,f_y=2\ ,f_z=11\ \\g_x=1\ ,g_y=-1\ ,g_z=1\\h_x=2x\ ,h_y=2y\ ,h_z=0

The Lagrange condition leads to

1=\lambda (1)+\mu (2x)\\2=\lambda (-1)+\mu (2y)\\11=\lambda (1)+\mu (0)

Operating and simplifying

1=\lambda+2x\mu\\2=-\lambda +2y\mu \\\lambda=11

Replacing the value of \lambda in the two first equations, we get

1=11+2x\mu\\2=-11 +2y\mu

From the first equation

\displaystyle 2\mu=\frac{-10}{x}

Replacing into the second

\displaystyle 13=y\frac{-10}{x}

Or, equivalently

13x=-10y

Squaring

169x^2=100y^2

To solve, we use the restriction h

x^2 + y^2 = 1

Multiplying by 100

100x^2 + 100y^2 = 100

Replacing the above condition

100x^2 + 169x^2 = 100

Solving for x

\displaystyle x=\pm \frac{10}{\sqrt{269}}

We compute the values of y by solving

13x=-10y

\displaystyle y=-\frac{13x}{10}

For

\displaystyle x= \frac{10}{\sqrt{269}}

\displaystyle y= -\frac{13}{\sqrt{269}}

And for

\displaystyle x= -\frac{10}{\sqrt{269}}

\displaystyle y= \frac{13}{\sqrt{269}}

Finally, we get z using the other restriction

x - y + z = 1

Or:

z = 1-x+y

The first solution yields to

\displaystyle z = 1-\frac{10}{\sqrt{269}}-\frac{13}{\sqrt{269}}

\displaystyle z = \frac{-23\sqrt{269}+269}{269}

And the second solution gives us

\displaystyle z = 1+\frac{10}{\sqrt{269}}+\frac{13}{\sqrt{269}}

\displaystyle z = \frac{23\sqrt{269}+269}{269}

Complete first solution:

\displaystyle x= \frac{10}{\sqrt{269}}\\\\\displaystyle y= -\frac{13}{\sqrt{269}}\\\\\displaystyle z = \frac{-23\sqrt{269}+269}{269}

Replacing into f, we get

f(x,y,z)=-0.4

Complete second solution:

\displaystyle x= -\frac{10}{\sqrt{269}}\\\\\displaystyle y= \frac{13}{\sqrt{269}}\\\\\displaystyle z = \frac{23\sqrt{269}+269}{269}

Replacing into f, we get

f(x,y,z)=2.4

The second solution maximizes f to 2.4

5 0
3 years ago
100 points plus brainliest question in the photo
klasskru [66]

The value is what the Y axis is when X is 8.

Draw a vertical line down from X=8 and see where the line crosses on the Y axis.


See the attached picture. The answer is Y = -4

5 0
3 years ago
Read 2 more answers
HELPP!! Points A and B are on the different sides on line l, the distance between point A and the line l is 10 in, the distance
ss7ja [257]

Answer:

7

Step-by-step explanation:

each way from 10 to 7 is 3 and 4 to 7 is 4

5 0
3 years ago
C. The number of men in a community is 2,400. If the ratio of women to men in the community is 5:4,
Ivahew [28]

Answer:

women : men

5. : 4

x. : 2400

x = 3000

i) 3000 + 2400= 5400

ii) 3000

iii) 3000 - ( 2400+400) = 200

7 0
2 years ago
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