Answer:
.615
Explanation:
Please refer to the attached file for the detailed step by step solution to the given problem.
Answer:
B
Explanation:
Question. You need to ask questions before you can set up to perform an experiment.
Answer:
163 kilograms per cubic feet.
Explanation:
To solve this problem, first we <u>convert 5.77 g/cm³ to kg/cm³</u>:
- 5.77 g/cm³ *
= 5.77x10⁻³ kg/cm³
Then we <u>convert kg/cm³ to kg/ft³</u>, by <em>converting cm³ to ft³</em>:
- 5.77x10⁻³ kg/cm³ *
= 163 kg/ft³
So the density is 163 kilograms per cubic feet.
Answer:
317 mL.
Explanation:
From the question given above, the following data were obtained:
Initial volume (V₁) = 250 mL
Initial temperature (T₁) = 373.15 K
Final temperature (T₂) = 473.15 K
Pressure = Constant
Final volume (V₂) =?
The final volume of the air sample can be obtained by using the Charles' law equation as illustrated below:
V₁/T₁ = V₂/T₂
250 / 373.15 = V₂ / 473.15
Cross multiply
373.15 × V₂ = 250 × 473.15
373.15 × V₂ = 118287.5
Divide both side by 373.15
V₂ = 118287.5 / 373.15
V₂ = 317 mL
Therefore, the final volume of the air sample is 317 mL
The molarity of a 250. mL H2SO4 solution that was made from a 20.0 mL of a 10.0 M stock solution is 0.8M.
<h3>How to calculate molarity?</h3>
The molarity of a solution can be calculated using the following expression:
CaVa = CbVb
Where;
- Ca = concentration of acid
- Cb = concentration of base
- Va = volume of acid
- Vb = volume of base
In this question;
- Ca = ?
- Va = 250mL
- Cb = 10M
- Vb = 20mL
Ca × 250 = 10 × 20
250Ca = 200
Ca = 200/250
Ca = 0.8M
Therefore, the molarity of a 250. mL H2SO4 solution that was made from a 20.0 mL of a 10.0 M stock solution is 0.8M.
Learn more about molarity at: brainly.com/question/2817451
