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Eva8 [605]
3 years ago
9

Consider an oil-to-oil double-pipe heat exchanger whose flow arrangement is not known. The temperature measurements indicate tha

t the cold oil enters at 15°C and leaves at 55°C, while the hot oil enters at 80°C and leaves at 40°C. Do you think this is a parallel-flow or counter-flow heat exchanger? Why? Assuming the mass flow rates of both fluids to be identical, determine the effectiveness of this heat exchanger.

Chemistry
1 answer:
Leya [2.2K]3 years ago
5 0

Answer:

.615

Explanation:

Please refer to the attached file for the detailed step by step solution to the given problem.

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<h3>Answer:</h3>

138 g SO₂

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Chemistry</u>

<u>Atomic Structure</u>

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<u>Stoichiometry</u>

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<h3>Explanation:</h3>

<u>Step 1: Define</u>

[Given] 2.16 moles SO₂

[Solve] grams (mass) SO₂

<u>Step 2: Identify Conversions</u>

[PT] Molar Mass of S - 32.07 g/mol

[PT] Molar Mass of O - 16.00 g/mol

Molar Mass of SO₂ - 32.07 + 2(16.00) = 64.07 g/mol

<u>Step 3: Convert</u>

  1. [DA] Set up:                                                                                                     \displaystyle 2.16 \ mol \ SO_2(\frac{64.07 \ g \ SO_2}{1 \ mol \ SO_2})
  2. [DA] Multiply/Divide [Cancel out units]:                                                         \displaystyle 138.391 \ g \ SO_2

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

138.391 g SO₂ ≈ 138 g SO₂

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