Question

Using law of cosines, what is angle X to the nearest degree

Answer 1

Answer:79 degrees

Step-by-step explanation:

Jus took the test hope this helps

Answer 2

Answer:

$X=68\°$

Step-by-step explanation:

we know that

Applying the law of cosines to the triangle of the figure

$yz^2=xy^2+xz^2-2(xy)(xz)cos(X)$

substitute the given values

$9^2=8^2+8^2-2(8)(8)cos(X)$

Solve for X

$81=64+64-128cos(X)$

$81=128-128cos(X)$

$128cos(X)=128-81$

$128cos(X)=47$

$cos(X)=\frac{47}{128}$

using a calculator

$X=cos^{-1}(\frac{47}{128})$

$X=68\°$