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OLga [1]
3 years ago
8

Find the zeros of g(x)=2x^2+32

Mathematics
1 answer:
expeople1 [14]3 years ago
4 0

Answer:

x = 4i, − 4i

Step-by-step explanation:

The roots (zeros) are the x values where the graph intersects the x-axis. To find the roots (zeros), replace y with 0 and solve for x

x = 4i, − 4i

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Answer:

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Step-by-step explanation:

cot x(csc x+1)=0

either cot x=0

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or csc x=-1

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K^2+5k-6=0 quadratic formula
s2008m [1.1K]
I hope this helps you



1.k^2+5k-6=0


a=1


b=5


c= -6


disctirminant =b^2-4ac


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disctirminant =49


x1= -(5)+ square root of 49/2.1



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Step-by-step explanation:

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