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3 years ago

What does it mean when the mark on the ramrod disappears into the barrel of the muzzleloader?

Physics

1 answer:

bagirrra123 [75]3 years ago

8 0

The firearm is unloaded.

The ramrod establishes whether the firearm is loaded or unloaded. It thrusts the bullet down the barrel. It is marked by wrapping some tape around it ( at the muzzle end ). This is to effectively signal if the muzzleloader is empty or loaded.

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What is the velocity of a 50 kg dog with 3000 j of kinetic energy

mezya [45]

Answer:

KE = 225000000 J

Explanation:

8 0

2 years ago

Read 2 more answers

Force X has a magnitude of 1260 pounds, and Force Y has a magnitude of 1530 pounds. They act on a single point at an angle of 4

weeeeeb [17]

Answer:

Fe= 2579.68 P

α= 24.8°

Explanation:

Look at the attached graphic

we take the forces acting on the x-y plane and applied at the origin of coordinates

FX = 1260 P , horizontal (-x)

FY = 1530 P , forming 45° with positive x axis

x-y components FY

FYx= - 1530*cos(45)° = - 1081.87 P

FYy= - 1530*sin(45)° = - 1081.87 P

Calculation of the components of net force (Fn)

Fnx= FX + FYx

Fnx= -1260 P -1081.87 P

Fnx= -2341.87 P

Fny=FYy

Fny= -1081.87 P

Calculation of the components of equilibrant force (Fe)

the x-y components of the equilibrant force are equal in magnitude but in the opposite direction to the net force components:

Fnx= -2341.87 P, then, Fex= +2341.87 P

Fny= -1081.87 P P, then, Fex= +1081.87 P

Magnitude of the equilibrant (Fe)

$F_{n} = \sqrt{(F_{nx})^{2} +(F_{ny})^{2} }$

$F_{e} =\sqrt{(2341.87)^{2}+(1081.87)^{2} }$

Fe= 2579.68 P

Calculation of the direction of equilibrant force (α)

$\alpha =tan^{-1} (\frac{F_{ny} }{F_{nx} } )$

$\alpha =tan^{-1} (\frac{1081.87 }{2341.87} )$

α= 24.8°

Look at the attached graphic

6 0

3 years ago

Chapter 38, Problem 001

Norma-Jean [14]

Answer:

a) $\lambda=2.95x10^{-6}m$

b) infrared region

Explanation:

Photon energy is the "energy carried by a single photon. This amount of energy is directly proportional to the photon's electromagnetic frequency and is inversely proportional to the wavelength. If we have higher the photon's frequency then we have higher its energy. Equivalently, with longer the photon's wavelength, we have lower energy".

Part a

Is provide that the smallest amount of energy that is needed to dissociate a molecule of a material on this case 0.42eV. We know that the energy of the photon is equal to:

$E=hf$

Where h is the Planck's Constant. By the other hand the know that $c=f\lambda$ and if we solve for f we have:

$f=\frac{c}{\lambda}$

If we replace the last equation into the E formula we got:

$E=h\frac{c}{\lambda}$

And if we solve for $\lambda$ we got:

$\lambda =\frac{hc}{E}$

Using the value of the constant $h=4.136x10^{-15} eVs$ we have this:

$\lambda=\frac{4.136x10^{15}eVs (3x10^8 \frac{m}{s})}{0.42eV}=2.95x10^{-6}m$

$\lambda=2.95x10^{-6}m$

Part b

If we see the figure attached, with the red arrow, the value for the wavelenght obtained from part a) is on the infrared region, since is in the order of $10^{-6}m$

4 0

3 years ago

A laser pulse with wavelength 532 nm contains 3.85 mj of energy. how many photons are in the laser pulse?

erastovalidia [21]

Answer:<em> </em><em>1.04 × 10¹⁶ photons</em>

Explanation:

1) Data:

E = 3.85mJj (mili joules) = 3.85×10⁻³ J

λ = 532 nm = 532 × 10⁻⁹ m

number of photons ?

2) Physical principles

a) The energy of a photon is given by the equation E = hν.

Where:

h is Planck's constant 6.62607004 × 10⁻³⁴ J×s
ν is the freguency of the light

b) The wavelength, λ, and the frequency, are related by the equation:

ν = c / λ, where c is the speed of light at vacuum, approximately 3.0 × 10⁸ m/s

3) Solution:

ν = c / λ = 3.0 × 10⁸ m/s / (538 nm) × 10⁹ nm/m = 5.576×10¹⁴ Hz

E = hν = 6.62607004 × 10⁻³⁴ J×s s × 5.576×10¹⁴ Hz = 3.69 × 10 ⁻¹⁹ J

Divide the total energy by the energy of one photon to find the number of photons:

3.85×10⁻³ J / 3.69 × 10 ⁻¹⁹ J-photon = 1.04 × 10¹⁶ photons ← answer

4 0

3 years ago

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A 10 Kg dog is running with a speed of 5.0 m/s what is the minimum work required to stop the dog

ra1l [238]

Answer:

25J

Explanation:

Given parameters:

Mass of the dog = 10kg

Speed of the dog = 5m/s

Unknown:

The minimum energy required to stop the dog = ?

Solution:

The dog is moving with a kinetic energy and to stop the dog, an equal amount of kinetic energy generated must be applied to the dog.

To find the kinetic energy;

K.E = $\frac{1}{2}$ m v²

m is the mass

v is the velocity

Now insert the parameters and solve;

K.E = $\frac{1}{2}$ x 10 x 5 = 25J

8 0

3 years ago