Explanation:
Given that,
Mass of disk = 1.2 kg
Radius = 0.07 m
Radius of rod = 0.11 m
Mass of small disk = 0.5 kg
Force = 29 N
Time t = 0.022 s

Distance d= 0.039 m
(I). We need to calculate the speed of the apparatus
Using work energy theorem



Where, m = total mass
v = velocity
F = force
d = distance
Put the value into the formula


(b). We need to calculate the angular speed of the apparatus
Using formula of torque





We need to calculate the angular speed of the apparatus
Using equation of angular motion

Put the value into the formula


(c). We need to calculate the angular speed of the apparatus
Using equation of angular motion

Put the value into the formula


Hence, This is required equation.
Answer:
(a) The speed of the target proton after the collision is:
, and (b) the speed of the projectile proton after the collision is:
.
Explanation:
We need to apply at the system the conservation of the linear momentum on both directions x and y, and we get for the x axle:
, and y axle:
. Now replacing the value given as:
,
for the projectile proton and according to the problem
are perpendicular so
, and assuming that
, we get for x axle:
and y axle:
, then solving for
, we get:
and replacing at the first equation we get:
, now solving for
, we can find the speed of the projectile proton after the collision as:
and
, that is the speed of the target proton after the collision.
Answer:
The answer is the kinetic energy of sled B after it crash is 6439j.
<span>the same amount of work being done over a longer period of time.</span>
I think it may be c i learned about this last year