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2 years ago

Find a number that is between 7/11 and /0.75

1 answer:

3 0

We can multiply the numerator and the denominator of 7/11 by 3, 4 and 9: 7/11 = 21/33 = 28/44 = 63/99. Than we can see that: 25/44 < 21/33 or 25/44 < 7/11 ( C is not correct ). Also: 77/99=0.777...and 76/99=0.7676... Therefore: 0.75 < 77/99 , 0.75 < 76/99. And since: 23/33 = 0.6969...: 7/11 < 23/33 < 0.75. Answer: D ) 23/33

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Solve the equation 12 - 27n2 = 0 9, 3 (2/3), (-2/3) (3/2), (-3/2) 2, 3

Norma-Jean [14]

(2/3),=(1/2), 3,4
.
............................

4 0

2 years ago

Given -8(x-3)=-32 prove x=7

AleksAgata [21]

Step-by-step explanation:

Plug x in :

-8(7-3) = -32

Distribute :

-56 - (-24) = -32

Subtract :

-32 = -32

7 0

3 years ago

Jimmy's backyard is rectangle that is 18 5/6 yards long and 10 2/5 yards wide Jim buy sod in pieces that are 1 1/3 yard long and

g100num [7]

Answer:

111 pieces of soda

Step-by-step explanation:

step 1

Find the area of the rectangular backyard

The area of the rectangular backyard is equal to

$A=LW$

where

$L=18\frac{5}{6}\ yd=\frac{18*6+5}{6}=\frac{113}{6}\ yd$

$W=10\frac{2}{5}\ yd=\frac{10*5+2}{5}=\frac{52}{5}\ yd$

substitute

$A=(\frac{113}{6})(\frac{52}{5})$

$A=\frac{5,876}{30}\ yd^2$

step 2

Find the area of one piece of sod

The area of the rectangular piece of sod is

$A=LW$

where

$L=1\frac{1}{3}\ yd=\frac{1*3+1}{3}=\frac{4}{3}\ yd$

$W=1\frac{1}{3}\ yd=\frac{1*3+1}{3}=\frac{4}{3}\ yd$

substitute

$A=(\frac{4}{3})^2\\\\A=\frac{16}{9}\ yd^2$

step 3

Find the pieces of sod needed

To find out how many whole pieces of sod will Jim need to buy to cover his backyard, divide the area of the backyard by the area of one piece of soda

$\frac{5,876}{30} : \frac{16}{9}=\frac{52,884}{480}=110.175$

Round up

111 pieces of soda

8 0

3 years ago

Each flower has a specific price. One tulip, one daisy, and 2 mums cost $4.20. On tulip, two daisies and one mum cost $3.80. Two

sineoko [7]

Answer:

The answer to your question is $5.60

Step-by-step explanation:

1 tulip + 1 daisy + 2 mums = $4.20 (1)

1 tulip + 2 daisies + 1 mum = $ 3.80 (2)

2 tulips + 2 mums = $4.80 (3)

1 tulip + 3 daisies + 2 mums = ?

tulip = t daisy = d mum = m

Process

1.- Find the price of each flower using system of equations

Solve equation 3 for tulip

2t = 4.80 - 2 m divide by 2 (4)

t = 2.40 - 1m

2.- Substitute equation 4 in equation 1 and 2

(2.4 - 1m) + 1 d + 2 m = 4.2

(2.4 - 1m) + 2d + 1 m = 3.8

3.- Simplify and solve for each flower

2.4 - 1m + 1d + 2m = 4.2

1d + 1m = 4.2 - 2.4

1d + 1m = 1.8 Equation (5)

2.4 - 1m + 2d + 1m = 3.8

2d = 3.8 - 2.4

2d = 1.4

d = 1.4/2

1d = 0.7

4.- Substitue d in equation 5

1(0.7) + 1m = 1.8

0.7 + 1m = 1.8

1m = 1.8 - 0.7

1m = 1.1

5.- Subtitute m in equation 4

1t = 2.40 - 1(1.1)

1t = 2.40 - 1.1

1t = 1.3

6.- Result

1 tulip + 3 daisies + 2 mums cost = 1.3 + 3(0.7) + 2(1.1)

= 1.3 + 2.1 + 2.2

= $5.6

8 0

2 years ago

HELP PLZZZZZZ!!!!!!!! F=fg/f+g-d solve for f F does not equal f SHOW YOUR WORK

Flura [38]

Is this even a problem

3 0

2 years ago