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Svetllana [295]
3 years ago
9

SHOW UR WORK PLEASE IM LTERALLY CRYING

Mathematics
1 answer:
GalinKa [24]3 years ago
4 0
Answer : 6 pieces
first you need to convert 3/4ths into 8th so you multiply
3/4 * 2 = 6/8
you can get 6 pieces of ribbon
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today a boat valued at $45,000.Thebvalue is expected to decrease at a rate of 8.5% each year.What is the value of the boat expec
Stels [109]

Current value of the boat = $45000

Rate at which the value decrease = 8.5%

Value decreased after 1 year = \frac{8.5}{100}\times45000=3825

Hence, value becomes = 45000-3825=41175

Value decreased after 2nd year =

\frac{8.5}{100}\times41175=3499.875

Hence, value becomes = 41175-3499.875=37675.125

Value decreased after 3 year =

\frac{8.5}{100}\times37675.125=3202.385

Hence, value becomes = 37675.125-3202.385=34472.74

So, value of the boat after 3 years becomes $34472.74

3 0
3 years ago
52 cards contains 4 aces, you randomly pick a card. X= your net of winnings
nirvana33 [79]

Chance of topdecking an ace is 1/13

8 0
4 years ago
What is 76912 divided by 92
Bogdan [553]
836 is the answer to this question.

5 0
3 years ago
Read 2 more answers
An artist can sell 20 compies of a painting for $100 each, but for each additional copy he makes the value of each painting will
ki77a [65]

Answer:

40 copies for $3000

Step-by-step explanation:

First: The Equation

y=(20+x)(100-x)

This shows how for every new painting, the price will go down.

y=2000+80x-x²

Convert it to standard form: ax²+bx+c

You can now choose to graph it or find the vertex form. For the limit of time, I will just use a graph.

The vertex, (40,3000), is your answer, where the x value is the number of paintings and the y value the money made.

4 0
4 years ago
Trees are subjected to different levels of carbon dioxide atmosphere with 6% of them in a minimal growth condition at 350 parts
podryga [215]

Answer:

Mean = 528 ppm

Standard deviation = 90.8 ppm

Step-by-step explanation:

Assuming a basis of 100 trees

6 trees with 350 ppm (minimal growth)

10 trees with 450 ppm (slow growth)

47 trees with 550 ppm (moderate growth)

37 trees with 650 ppm (rapid growth)

Mean = xbar = Σx/N

x = each variable

xbar = mean

N = number of variables = 100

Σx = sum of all variables = sum of all the ppm = (6×350) + (10×450) + (47×550) + (37×550) = 52800

xbar = 52800/100 = 528 ppm

Standard deviation = σ = √[Σ(x - xbar)²/N]

x = each variable

xbar = mean = 528

N = number of variables = 12

Σ(x - xbar)² = [6(350 - 528)²] + [10(450 - 528)²] + [47(550 - 528)²] + [37(650 - 528)²] = 824400

σ = √[Σ(x - xbar)²/N] = √(824400/100) = 90.8 ppm

5 0
3 years ago
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