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Svetllana [295]
3 years ago
9

SHOW UR WORK PLEASE IM LTERALLY CRYING

Mathematics
1 answer:
GalinKa [24]3 years ago
4 0
Answer : 6 pieces
first you need to convert 3/4ths into 8th so you multiply
3/4 * 2 = 6/8
you can get 6 pieces of ribbon
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The area of the square, the
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Answer:

B.

Step-by-step explanation:

I think your question is missed of key information, allow me to add in and hope it will fit the original one.  

Please have a look at the attached photo.  

My answer:

As given in the question, we know that:

The ratio of the area of the circle to the area  of the square is π/4

  • The formula to find the volume of the cone is:

V = 1/3*the height*the base area

<=> V1 = 1/3*h*πr^{2}

  • The formula to find the volume of the pyramid is:

V2 = 1/3*the height*the base area

<=> V =  1/3*h*4r^{2}

=> the ratio of volume of the cone to the pyramid is:

= \frac{V1}{V2}

= (1/3*h*πr^{2} ) / ( 1/3*h*4r^{2} )

= π/4

S we can conclude that the volume of the cone equals π/4  the volume of the  pyramid

Hope it will find you well.

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Which expression is equivalent to StartFraction StartRoot 2 EndRoot Over RootIndex 3 StartRoot 2 EndRoot EndFraction? One-fourth
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Question:

Which expression is equivalent to

\frac{\sqrt{2}}{\sqrt[3]{2}}

Answer:

\frac{\sqrt{2}}{\sqrt[3]{2}} =2^{\frac{1}{6}} = \sqrt[6]{2}

Step-by-step explanation:

Given

\frac{\sqrt{2}}{\sqrt[3]{2}}

Required

Simplify

From laws of indices;

\sqrt[n]{x} =x^{\frac{1}{n}}

So, the expression can be rewritten as

\frac{\sqrt{2}}{\sqrt[3]{2}} = \frac{{2^{\frac{1}{2}}}}{2^{\frac{1}{3}}}

Also, from laws of indices

\frac{x^a}{x^b} = x^{a-b}

So, the expression is further solved to:

\frac{\sqrt{2}}{\sqrt[3]{2}} =2^{\frac{1}{2} - \frac{1}{3}

Solve exponents as fraction

\frac{\sqrt{2}}{\sqrt[3]{2}} =2^{\frac{3-2}{6}}

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This can be rewritten as

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