Hi there!
In math terms, when we think of the words "Taken away", we immediately think of subtraction/subtracting. So, the symbol that you're looking for looks sort of like a dash.
- is what it looks like.
Hope this helps!
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Answer:
It is known that in the periodic inventory, the accounting record of the stock of goods will occur only at the end of a certain period with the physical count of the existing quantities. Consider the following CVM information = 500.00; Initial Inventory = 700.00 and Purchases = 800.00. Applying the concept of periodic inventory and applying the formula for calculating the CMV, determine the value of the final stock.
ALTERNATIVES
Final stock of 2,000.00.
Final stock of 1,500.00.
Final stock of 1,300.00.
Final stock of 1,200.00.
Final stock of 1,000.00.
Final Stock (EF) = 1,000.00
Step-by-step explanation:
Alternative E - Final stock of 1,000.00.
Given That,
CMV = 500,00
Initial Stock (EI) = 700.00
Purchases (C) = 800.00
Final Stock (EF) = ?
Formula
CMV = Initial Stock (EI) + Purchases (C) - Final Stock (EF)
CMV = EI + C - EF
500 = 700 + 800 - EF
500.00 = 700.00 + 800.00 -X
500 = 1500- EF
500.00 = 1,500.00-X
EF = 1500-500
X = 1,000.00
EF = 1,000.00
Therefore, the final stock is 1,000
The answer would be b A≈1636.8
Suppose that a>b>1, then
and
Therefore, since 2<3<7,
Choose an arbitrary x>1. You have that a takes the greatest values at x, c takes the smallest value at x. Thus,
a>b>c and
Answer: correct option is B.
Area of the figure = 806.5 in²
Solution:
Length of the rectangle = 16 in
Breadth of the rectangle = 9 in
Area of the rectangle = length × breadth
= 16 × 9
Area of the rectangle = 144 in²
Base of the triangle = 31 in
Height of the triangle = 20 in
Area of the triangle =
Area of the triangle = 310 in²
Parallel sides of the trapezium = 16 in and 31 in
Height of the trapezium = 35 – 20 = 15 in
Area of the trapezium =
Area of the trapezium = 352.5 in²
Area of the figure = Area of rectangle + Area of triangle + Area of trapezium
= 144 in² + 310 in² + 352.5 in²
Area of the figure = 806.5 in²