Answer:
all the time
Step-by-step explanation:
Answer:
Step-by-step explanation:
\mathrm{Multiply\:the\:numerator\:and\:denominator\:by:}\:100
\mathrm{Multiply\:the\:quotient\:digit}\:\left(0\right)\:\mathrm{by\:the\:divisor}\:505
\mathrm{Subtract}\:0\:\mathrm{from}\:23
1mm:1m
since its just one to one, thats the ratio
3x-5=19-x
3x-5-19+x=0
4x-24=0
4x=24
x=6
X = -3.
The distance from p(-9, 0, 0) is
d = sqrt((x+9)^2 + y^2 + z^2)
The distance from q(3,0,0) is
d = sqrt((x-3)^2 + y^2 + z^2)
Let's set them equal to each other.
sqrt((x+9)^2 + y^2 + z^2) = sqrt((x-3)^2 + y^2 + z^2)
Square both sides, then simplify
(x+9)^2 + y^2 + z^2 = (x-3)^2 + y^2 + z^2
x^2 + 18x + 81 + y^2 + z^2 = x^2 - 6x + 9 + y^2 + z^2
18x + 81 = - 6x + 9
24x + 81 = 9
24x = -72
x = -3
So the desired equation is x = -3 which defines a plane.
