1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Nookie1986 [14]
3 years ago
8

Billy Thornton borrowed $150,000 at a rate of 7.25%, simple interest, with interest paid at the end of each month. The bank uses

a 360-day year.
How much interest would Billy have to pay in a 30-day month?
Select the correct answer.
a. $904.75
b. $907.75
c. $903.25
d. $909.25
e. $906.25
Mathematics
2 answers:
kipiarov [429]3 years ago
8 0

Option e

The interest Billy has to pay in a 30 day month is $ 906.25

<u>Solution:</u>

Given, Billy Thornton borrowed $150,000 at a rate of 7.25%, simple interest, with interest paid at the end of each month.  

The bank uses a 360-day year.  

<em><u>The simple interest is given as:</u></em>

\text { Simple interest }=\frac{\text { amount } \times \text {rate} \times \text {time}}{100}

Where amount is principal amount,

rate is interest rate % per year

time is number of years  

Here in our problem, amount = $150000

\text { rate } \%=7.25 \% \text { per year }=\frac{7.25}{360 \text { days }} \text { per day }

We need to calculate for 30 day month

Time = 30 days

Plugging the values in formula, we get,

\begin{array}{l}{\text { simple interest }=\frac{150000 \times \frac{7.25}{360} \times 30}{100}} \\\\ {=1500 \times \frac{7.25}{12}=906.25}\end{array}

Hence interest to be paid in a 30 day month is $ 906.25. Thus Option e is correct

Marina86 [1]3 years ago
4 0
E: $906.25
$150,000 * 0.725= 108750 (to find the total amount billy has to pay over the year)
108750/12= 9062.5
You might be interested in
What is the third quartile of this data set? <br> 20, 21, 24, 25, 28, 29, 35, 37, 42
nata0808 [166]

Answer:

36

Step-by-step explanation:

⇒The question is on third quartile

⇒To find the third quartile we calculate the median of the upper half of the data

Arrange the data in an increasing order

20, 21, 24, 25, 28, 29, 35, 37, 42

Locate the median, the center value

<u>20, 21, 24, 25</u>, 28, <u>29, 35, 37, 42</u>

<u />

The values 20, 21, 24, 25 ------------lower half used in finding first quartile Q1

The value 28 is the median

The vlaues 29, 35, 37, 42...............upper half used in finding 3rd quartile Q3

Finding third quartile Q3= median of the upper half

upper half= 29,35,37,42

median =( 35+37)/2 = 36

6 0
3 years ago
What is the equation for the line described in #9And #10?
ValentinkaMS [17]

Answer: it is definitely c. y=3x+2

Step-by-step explanation: solve the first equation and then plug in

5 0
2 years ago
Life is a pain, I need help ASAP. NO GOD PLEASE NO, NO, NOOOOOOOOO
romanna [79]
The answer should be 23
6 0
3 years ago
Evaluate 3 square root of 0.008
statuscvo [17]

Answer:

I think the answer is 0.2683281573

4 0
3 years ago
What is 1/7 times 2/3
ziro4ka [17]
2/21or ethier 2/7 tht will be the answer maybe.
6 0
3 years ago
Other questions:
  • Write the equation of a line in point slope form that has a slope of − 3/4 and passes through the point (4, 5). Please explain h
    9·1 answer
  • Please help simple pre algebra!!!​
    14·2 answers
  • Please please use explanation with answer
    15·1 answer
  • Audrey is buying a new car for 32,998 she plans to make a down payment of 4200 if she’s to make monthly payments of 525 for the
    7·2 answers
  • Alvin is 15 years younger than Elga. The sum of their ages is 25. What is Elga’s age
    10·1 answer
  • If y varies inversely as x and y = –9 when x = –11, find y when x = 66.
    5·2 answers
  • Determine how many solutions the equation has. If one solution, state the value of x.
    11·1 answer
  • Given : 3x + 2(x — 5) = 32<br> prove : x = 84
    9·1 answer
  • Find the value of each of the following: exponents
    7·1 answer
  • Which ordered pair is a solution to the inequality in the graph?
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!