$\displaystyle x^2 - 8x + 41 = 0 \\\\ \Delta=b^2-4ac \\ \Delta=(-8)^2-4\cdot1\cdot41 \\ \Delta=64-164 \\ \Delta=-100 \\ \\ X_{1,2}= \frac{-b\pm i \sqrt{-\Delta} }{2a} = \frac{8 \pm 10i}{2} \\ \\ X1=4-5i \\ \\ X2=4+5i$

5 0

3 years ago

HELP EMERGENCY!!!!!! What is the equation of the line? Y=3x-1 Y=-3x Y=3x+1 Y=3x

ch4aika [34]

<h2>Answer:</h2>

By process of elimination, we can eliminate:

A: y = 3x - 1
C: y = 3x + 1
B: y = -3x

A and C don't work because the given line has it's y-intercept at the origin, therefore, no y-intercept is written. B is not it either because the line does not go down from left to right, therefore, the slope is not negative.

The answer is D: y = 3x because since the line goes up from left to right, the slope is positive, and the y-intercept is the origin, so the equation will have no b.

7 0

2 years ago