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3 years ago

Is 3 times 2/7 less than 3

Mathematics

1 answer:

kenny6666 [7]3 years ago

3 0

Answer:

Yes

Step-by-step explanation:

You can set up your proportion as $\frac{3}{1}$ * $\frac{2}{7}$ you then multiply across to get $\frac{6}{7}$ . Since this number is less than 1, it's definitely less than 3.

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Calculate the length of an arc

jek_recluse [69]

Easy peasy
remember that the arc is a part of the perimiter of the circle aka circumference
also 360 degrees=circle

we are given the radius
calculate circumference
c=2pi times r
r=14
c=pi times 2 itimes 14
c=28pi

100 degrees is the arc

find what fraction of the circumferece thei srepresents
whole=360
100/360=10/36=5/18
so if circumference=28pi then multiply 5/18 by that
5/18 times 28pi=140pi/18=70pi/9
legnth=(70pi)/9 cm
if you were to aprox pi to 3.14 then the answer would be
24.4222222 cm

3 0

4 years ago

kherson [118]

Answer:

$25.57

Step-by-step explanation:

First, you have to multiply $5.29 by 2 because she wants to spend $5.29 on 2 pairs of socks.

5.29 * 2 = $10.58

Then you want to add $10.58 and $14.99 together.

$10.58 + $14.99 = $25.57

3 0

3 years ago

180 = −9d + 9 d = I need to find what d is

omeli [17]

Answer:

-19

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Help me ...........................

Iteru [2.4K]

Answer:

They will be able to.

Step-by-step explanation:

You first want to make sure the first three families have enough to eat.

$6\frac{1}{2} - 2\frac{7}{8} = 3\frac{5}{8}$

For further explanation look at the first image.

$3\frac{5}{8} > 2\frac{7}{8}$

Just to make sure

$3\frac{5}{8} - 2\frac{7}{8}=\frac{3}{4}$

For further explanation look at the second image.

The rest of the images show a model solution.

7 0

3 years ago

Dinosaur fossils are often dated by using an element other than carbon, like potassium-40, that has a longer half life (in this

Firlakuza [10]

The amount of substance left of a radioactive element of half life, $t_{\frac{1}{2}}$ after a time, t, is given by:

$N(t)=N_0\left( \frac{1}{2} \right)^ \frac{t}{t_{ \frac{1}{2} }}$

Given that <span>potassium-40 has a half life of approximately 1.25 billion years.

The number of years it will take for 0.1% of potassium-40 to remain is obtained as follows:

$0.1=100\left( \frac{1}{2} \right)^ \frac{t}{1.25}} \\ \\ \Rightarrow\left( \frac{1}{2} \right)^ \frac{t}{1.25}}=0.001 \\ \\ \Rightarrow\frac{t}{1.25}\ln\left( \frac{1}{2} \right)=\ln(0.001) \\ \\ \Rightarrow \frac{t}{1.25}= \frac{\ln(0.001)}{\ln\left( \frac{1}{2} \right)} =9.966 \\ \\ t=9.966(1.25)=12.5$

Therefore, </span><span>the maximum age of a fossil that we could date using 40k is 12.5 billion years.</span>

3 0

3 years ago