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posledela
3 years ago
5

Find x. please give calculation too. please

Mathematics
1 answer:
ELEN [110]3 years ago
5 0

log_{2}x -log_{4}x= -2 \\ \\ log_{2}x -\frac{log_{2}x}{log_{2}4}= -2  \\ \\ log_{2}x*(1-\frac{1}{log_{2}4})=-2 \\ \\ log_{2}x*(1-\frac{1}{2})=-2 \\ \\\frac{1}{2}*log_{2}x=-2 \\ \\ log_{2}x=-4,   \\ \\ x=2^{-4} = \frac{1}{2^{4}}=0.0625

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it rained nine days in the month of april .based on this ,what is the probaility that is does not rain on the first day of may?​
attashe74 [19]
<h3>Answer:     7/10</h3>

==========================================================

Explanation:

There are 30 days in April. Since it rained 9 of those days, the empirical probability of it raining in April is 9/30 = (3*3)/(3*10) = 3/10.

If we assume that the same conditions (ie weather patterns) hold for May, then the empirical probability of it raining in May is also 3/10. By "raining in May", I mean specifically raining on a certain day of that month.

The empirical probability of it not raining on the first of May is therefore...

1 - (probability it rains)

1 - (3/10)

(10/10) - (3/10)

(10-3)/10

7/10

We can think of it like if we had a 10 day period, and 3 of those days it rains while the remaining 7 it does not rain.

6 0
3 years ago
Mrs. Daly's reading classes were surveyed about their reading preferences. The data is summarized in the table below.
andriy [413]

Answer:

Required probability is 0.19

Step-by-step explanation:

The two-way table for the given data is,

                              Fiction                Non-Fiction                Total

9th grade                35                            8                             43

10th grade               52                            12                           64

Total                        87                            20                           107

It is required to find the probability of the students who prefer to read non-fiction novels, given that they are in 9th grade.

That is, to find the conditional probability P(Non-fiction| 9th\ grade).

Now, P(A|B)=\dfrac{P(A\bigcap B)}{P(B)}

So, we get,

P(Non-fiction| 9th\ grade)=\dfrac{(Non-fiction\bigcap 9th\ grade)}{P(9th\ grade)}\\\\P(Non-fiction| 9th\ grade)=\dfrac{8}{43}\\\\P(Non-fiction| 9th\ grade)=0.19

<h3>Thus, the required probability is 0.19.</h3>
5 0
3 years ago
1/4 divided by 2/3 show work pls
NARA [144]
\dfrac{1}{4}:\dfrac{2}{3}=\dfrac{1}{4}\cdot\dfrac{3}{2}=\dfrac{1\cdot3}{4\cdot2}=\boxed{\frac{3}{8}}
5 0
3 years ago
What is 7/6 ÷ 4 in simplest form
serg [7]
\frac{7}{6} \div 4= \frac{7}{6} \times \frac{1}{4} = \frac{7\times 1}{6\times 4} = \frac{7}{24}

7/24 is your answer :)
7 0
3 years ago
Read 2 more answers
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Tema [17]
Should be this .. hoped this helped:)

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