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3 years ago

Find the area of a regular decagon with radius 4 cm

2 answers:

8 0

$A = \frac{5}{2}t^{2} \sqrt{5 + 2 \sqrt{5} }$

$A = \frac{5}{2} (4)^{2} \sqrt{5 + 2(2.236067978)} }$

$A = \frac{5}{2} (16) \sqrt{5 + 4.472135956}$

$A = 40 \sqrt{9.472135956}$

$A = 40(3.077683537)$

$A = 123.1073415cm^{2}$

emmasim [6.3K]3 years ago

5 0

The area is 123.1073415 cm

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Answer:

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3 years ago

Physics students were modeling the height of a ball once it was dropped from the top of a 10 foot ladder. The

julsineya [31]

Answer:

Interval notation: [0, 2.236]

Set Builder notation: $\{t\ |\ 0\le t\le 2.236\}$

Step-by-step explanation:

Given that:

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The domain of the function in Interval and set builder notation.

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Domain of a function is defined as the set of valid input values that can be given to the function for which the function is defined.

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Maximum value for time can be 2.236 seconds.

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3 years ago

Find S18 for geometric series given a5=-6 and a2= -48

Ganezh [65]

an = a1r^(n-1)

a5 = a1 r^(5-1)

-6 =a1 r^4

a2 = a1 r^(2-1)

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divide

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---------------- yields 1/8 = r^3 take the cube root or each side

-48 = a1 r 1/2 = r

an = a1r^(n-1)

an = a1 (1/2)^ (n-1)

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divide by 1/2

-96 = a1

an = -96 (1/2)^ (n-1)

the sum

Sn = a1[(r^n - 1/(r - 1)]

S18 = -96 [( (1/2) ^17 -1/ (1/2 -1)]

=-96 [ (1/2) ^ 17 -1 /-1/2]

= 192 * [-131071/131072]

approximately -192

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3 years ago

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3 years ago

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kati45 [8]

Answer:

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3 years ago

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