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fiasKO [112]
3 years ago
14

If y=2x-3 find the value of y when x=2

Mathematics
2 answers:
Evgesh-ka [11]3 years ago
8 0
Y = 2x - 3
Y = 2(2) - 3
Y = 4 - 3
Y = 1.

The y value or y coordinate is 1.
likoan [24]3 years ago
8 0
Y=2x-3
y=2(2)-3
y=4-3
Y = 1   Hope this helped!

-Twix
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Express 5/8 as a percent. 62.5% 40% 58% 62% Express as a percent.
AveGali [126]
5/8 as a percentage is 62.5 

hope i helped :D
6 0
3 years ago
Read 2 more answers
Explain why each of the following integrals is improper. (a) 4 x x − 3 dx 3 Since the integral has an infinite interval of integ
erma4kov [3.2K]

Answer:

a

   Since the integral has an infinite discontinuity, it is a Type 2 improper integral

b

   Since the integral has an infinite interval of integration, it is a Type 1 improper integral

c

  Since the integral has an infinite interval of integration, it is a Type 1 improper integral

d

     Since the integral has an infinite discontinuity, it is a Type 2 improper integral

Step-by-step explanation:

Considering  a

          \int\limits^4_3 {\frac{x}{x- 3} } \, dx

Looking at this we that at x = 3   this  integral will be  infinitely discontinuous

Considering  b    

        \int\limits^{\infty}_0 {\frac{1}{1 + x^3} } \, dx

Looking at this integral we see that the interval is between 0 \ and  \  \infty which means that the integral has an infinite interval of integration , hence it is  a Type 1 improper integral

Considering  c

       \int\limits^{\infty}_{- \infty} {x^2 e^{-x^2}} \, dx

Looking at this integral we see that the interval is between -\infty \ and  \  \infty which means that the integral has an infinite interval of integration , hence it is  a Type 1 improper integral

Considering  d

        \int\limits^{\frac{\pi}{4} }_0  {cot (x)} \, dx

Looking at the integral  we see that  at  x =  0  cot (0) will be infinity  hence the  integral has an infinite discontinuity , so  it is a  Type 2 improper integral

     

7 0
3 years ago
Select the two statements that are true about the equation y+6=−10(x−3).
qwelly [4]

I have taken that test (although I don't see you're statements)

I believe the statements to choose from are:

A.) The slope of the line is −10.

B.) The slope of the line is 3.

C.) One point on the line is (3, 6).

D.) One point on the line is (3,−6)

<u>The answers are:</u>

A.) The slope of the line is -10

D.) One point on the line is (3,-6)

<u>Explanation: </u>

The given equation of line is (1).  The point slope form of a line is  (2)  Where m is the slope of line and (x₁,y₁) are points.  On comparing (1) and (2) we get The slope of given line is -10 and the line passing through the points (3,-6).

6 0
3 years ago
Help please and thank you
aksik [14]
Remember
(a^b)^c=a^{bc}
and
\frac{x^a}{x^b}=x^{a-b}


so

\frac{(7^2)^5}{7^{-6}}=
\frac{7^{2*5}}{7^{-6}}=
\frac{7^{10}}{7^{-6}}=
7^{10-(-6)}=
7^{10+6}=
7^{16}

the answer is D
5 0
3 years ago
CHECK ANSWERS -
Tju [1.3M]
Both are correct.

Good job!
6 0
3 years ago
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