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Sonja [21]
3 years ago
11

Point Z on a coordinate grid is at (-1,3). If the point is reflected across the line y=-x, what are the coordinates of its image

?
Mathematics
1 answer:
Neko [114]3 years ago
4 0
(-3,1)

x,y > -y,-x

Therefore (-1,3) is (-3,1)
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Find the area of a triangle with a base length of 3 units and a height of 4 units.
svetlana [45]

Answer:

6 square units

Step-by-step explanation:

The area of a triangle can be calculated by multiplying the triangle's base by its height, and then dividing the result by 2. As an algebraic expression, this would be \frac{bh}{2}, where b is the triangle's base and h is the triangle's height. In this case, we know that b=3 and h=4. Therefore, the area of this triangle is \frac{3*4}{2} =\frac{12}{2} =6 square units. Hope this helps!

6 0
2 years ago
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Vilka [71]

Answer:

70,110,110,110

Step-by-step explanation:

I'm Asian and I was less than 5 minutes

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3 years ago
Give the equations of 3 lines that are parallel to the line with the equation y=3x+2
ruslelena [56]
Y= 3x + 1
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6 0
2 years ago
A media poll of 500 air travelers surveyed in national airports found that 370 favor tighter security procedures in boarding pla
serg [7]

Answer:

92% Confidence interval:  (0.7078,0.7722)

Step-by-step explanation:

We are given the following in the question:

Sample size, n = 500

Number of travelers who favor tight security, x = 370

\hat{p} = \dfrac{x}{n} = \dfrac{370}{500} = 0.74

92% Confidence interval:

\hat{p}\pm z_{stat}\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}

z_{critical}\text{ at}~\alpha_{0.08} = \pm 1.645

Putting the values, we get:

0.74\pm 1.645(\sqrt{\dfrac{0.74(1-0.74)}{500}}) = 0.74\pm 0.0322\\\\=(0.7078,0.7722)

3 0
3 years ago
10.
vodomira [7]
<h3>Solution:</h3>
  • Given, side (a) = x+3
  • We know, surface area of a cube = 6a^2
  • Therefore, the surface area of the cube
<h3> </h3><h3>6(x + 3) ^{2}  \\  = 6( {x}^{2}  + 6x + 9) \\  = 6 {x}^{2}  + 36x + 54</h3><h3>Answer:</h3>

The answer is

{6x}^{2}  + 36x + 54

<h3>Hope it helps.</h3>

Sorry for delay

3 0
2 years ago
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