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3 years ago

What can be concluded about the spread of the histogram and yes it has a pic

Mathematics

2 answers:

zepelin [54]3 years ago

6 0

Answer:

histogram is not symmetrical

Step-by-step explanation:

nlexa [21]3 years ago

4 0

The histogram is not symmetrical

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PLEASE HELP will mark brainliest! 10 points

Alik [6]

Answer:

(D)

Step-by-step explanation:

Angles 2 & 6 are called corresponding angles in the diagram and they are congruent if the lines c & d are parallel. Since they are, that means lines c & d are parallel.

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3 years ago

What is GC? A. 9 B. 12 C. 13 D. 14

Naily [24]

Answer:

C 13

Step-by-step explanation:

i think answer its c

3 0

2 years ago

Read 2 more answers

What equations are equivalent to -4+(4+5)?

Igoryamba

Answer:

-4 + 9

9- 4

Step-by-step explanation:

4 0

3 years ago

The 1992 world speed record for a bicycle (human-powered vehicle) was set by Chris Huber. His time through the measured 200 m st

Reil [10]

Answer:

a) 30.726m/s and b) 5.5549s

Step-by-step explanation:

a.) What was Chris Huber’s speed in meters per second(m/s)?

Given the distance and time, the formula to obtain the speed is

$v=\frac{d}{t}$ .

Applying this to our problem we have that

$v=\frac{200m}{6.509s}= 30.726m/s$ .

So, Chris Huber’s speed in meters per second(m/s) was 30.726m/s.

b) What was Whittingham’s time through the 200 m?

In a) we stated that $v=\frac{d}{t}$ . This formula implies that

$t=\frac{d}{v}$ .

First, observer that $19\frac{km}{h} =19,000\frac{m}{h}=\frac{19,000}{3,600}m/s= 5.2777m/s$ .

Then, Sam Whittingham speed was equal to Chris Huber’s speed plus 5.2777 m/s. So, $v=30.726\frac{m}{s} +5.2777\frac{m}{s}= 36.003 m/s.$

Then, applying 1) we have that

$t=\frac{200m}{36.003m/s}=5.5549s.$

So, Sam Whittingham’s time through the 200 m was 5.5549s.

5 0

3 years ago

I need help with this last question. Please help

dusya [7]

The angle of STV would be 140 degrees.

3 0

3 years ago