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2 years ago

Corey has 510 marbles he fills one jar with 165 marbles how many are not in the jar

Mathematics

2 answers:

Luba_88 [7]2 years ago

4 0

Answer:

510-165=345.

Step-by-step explanation:

Well if you subtract 510-165 you would get 345. Therefore your answer would be " There are 345 marbles that are not in the jar."

Allushta [10]2 years ago

3 0

Answer:

The answer is 345.

Step-by-step explanation:

I got this answer by:

First, I took 510 and subtracted 165 and 165 and that equals 345. To check my work I added 165 and 345 Which gave me a sum of 510.

Hope this helps!!

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The scheduled arrival time for a daily flight from Boston to New York is 9:30 am. Historical data show that the arrival time fol

Galina-37 [17]

Answer:

Step-by-step explanation:

Let x be a random variable representing the flight arrival time from Boston to New York.

For a uniform probability distribution, the notation is

X U(a, b) where a is the lowest value of x and b is the lowest value of x

The probability density function, f(x) = 1/(b - a)

Mean, µ = (a + b)/2

Standard deviation, σ = √(b - a)²/12

From the information given, the time difference in minutes is 9:57 - 9:07 = 50 minutes. Therefore,

a = 0

b = 50

µ = (0 + 50)/2 = 25

σ = √(50 - 0)²/12 = 14.43

b) converting to minutes, it is 9:30 - 9:07 = 23 minutes

the probability that a flight arrives late(later than 9:30 am) is expressed as P(x > 23)

f(x) = 1/(50) = 0.02

P(x > 23) = (50 - 23)0.02 = 0.54

7 0

2 years ago

I need the answer fast

Fantom [35]

Answer:

B. What was the highest temperature this month?

Step-by-step explanation:

Rory is recording the highest temperature for the duration of the day for month's worth of data.

B. is the easiest one to answer, as you simply will have to look for the greatest number within the set, and that will be the answer.

A. is too broad, and does not imply that only the "high temperature" is needed, rather just a leveled temperature within day in that month.

C. is the opposite of what Rory had recorded, and without data, he cannot answer it.

D. is answerable as well, but, again, the only temperature recorded is the high temperature. Temperature can fluctuate depending on the time of the day, and can be in the 50s one hour and the 90s in another.

5 0

2 years ago

The local library charges 6 cents for each day a book is overdue plus a one-time record keeping fee of 19 cents. the function ta

Natasha2012 [34]

B. 241
Because (6•37)+19=222+19=241 cents

5 0

3 years ago

During a sale, cameras were discounted 30% from their original price of $295.99. To the nearest cent, how much was the camera du

Elina [12.6K]

Answer:

207.193

Step-by-step explanation:

295.99 - 30% ...........

3 0

2 years ago

Read 2 more answers

Discuss the continuity of the function on the closed interval.Function Intervalf(x) = 9 − x, x ≤ 09 + 12x, x > 0 [−4, 5]The f

quester [9]

Answer:

It is continuous since $\lim_{x\to 0^{-}} = f(0) = \lim_{x \to 0^{+} f(x)$

Step-by-step explanation:

We are given that the function is defined as follows $f(x) = 9-x, x\leq 0$ and $f(x) = 9+12x, x>0$ and we want to check the continuity in the interval [-4,5]. Note that this a piecewise function whose only critical point (that might be a candidate of a discontinuity) x=0 since at this point is where the function "changes" of definition. Note that 9-x and 9+12x are polynomials that are continous over all $\mathbb{R}$ . So F is continous in the intervals [-4,0) and (0,5]. To check if f(x) is continuous at 0, we must check that

$\lim_{x\to 0^{-}} = f(0) = \lim_{x \to 0^{+} f(x)$ (this is the definition of continuity at x=0)

Note that if x=0, then f(x) = 9-x. So, f(0)=9. On the same time, note that

$\lim_{x\to 0^{-}} f(x) = \lim_{x\to 0^{-}} 9-x = 9$ . This result is because the function 9-x is continous at x=0, so the left-hand limit is equal to the value of the function at 0.

Note that when x>0, we have that f(x) = 9+12x. In this case, we have that

$\lim_{x\to 0^{+}} f(x) = \lim_{x\to 0^{+}} 9+12x = 9$ . As before, this result is because the function 9+12x is continous at x=0, so the right-hand limit is equal to the value of the function at 0.

Thus, $\lim_{x\to 0^{-}} = f(0) = \lim_{x \to 0^{+} f(x)=9$ , so by definition, f is continuous at x=0, hence continuous over the interval [-4,5].

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3 years ago

Read 2 more answers