The equation that represents the line that is perpendicular is
3y + 5x = -42
The standard equation of a line in point-slope form is expressed as:

- m is the slope of the lne
- (x1, y1) is any point on the line.
- Given the equation y = 3/2x + 1, the slope of the line is 3/5
- The s<u>lope of the line perpendicular</u> is -5/3
Substitute the point (-12, 6) and the slope m = -5/3 into the equation above to have:

Hence the equation that represents the line that is perpendicular is
3y + 5x = -42
Learn more on equation of a line here:brainly.com/question/19417700
Answer:
The correct answer is x=5
Answer:

Step-by-step explanation:
we have

we know that

substitute

Factor 2
![2[(2)x+(7)]](https://tex.z-dn.net/?f=2%5B%282%29x%2B%287%29%5D)

Answer: 1.08T and (1+8/100)T
Step-by-step explanation:
Given: The average temperature two Sundays ago was T degrees Celsius.
Since, last Sunday, the average temperature was 8% higher than the average temperature two Sundays ago.
⇒ The average temperature last Sunday
Since 8%=0.08
Therefore, The average temperature last Sunday
⇒ The average temperature last Sunday
⇒ The average temperature last Sunday
⇒ The average temperature last Sunday
Thus, the right option is 1.08T and (1+8/100)T.
Answer:
There are 1% probability that the last person gets to sit in their assigned seat
Step-by-step explanation:
The probability that the last person gets to sit in their assigned seat, is the same that the probability that not one sit in this seat.
If we use the Combinatorics theory, we know that are 100! possibilities to order the first 99 passenger in the 100 seats.
LIke we one the probability that not one sit in one of the seats, we need the fraction from the total number of possible combinations, of combination that exclude the assigned seat of the last passenger. In other words the amount of combination of 99 passengers in 99 seats: 99!
Now this number of combination of the 99 passenger in the 99 sets, divide for the total number of combination in the 100 setas, is the probability that not one sit in the assigned seat of the last passenger.
P = 99!/100! = 99!/ (100 * 99!) = 1/100
There are 1% probability that the last person gets to sit in their assigned seat