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2 years ago

9

When you multiply any odd number by 2, the result is an odd number Is the following statement always true, sometimes true, or ne

ver true?

1 answer:

Strike441 [17]2 years ago

5 0

Answer:

Always true

Step-by-step explanation:

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2 years ago

Why is it that -log(x+8)=4-log(x-7) has no solution? (they are log base 2)

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$-log(x+8)=4-log(x-7)$

$-\log _{10}\left(x+8\right)+\log _{10}\left(x+8\right)=4-\log _{10}\left(x-7\right)+\log _{10}\left(x+8\right)$

$0=4-\log _{10}\left(x-7\right)+\log _{10}\left(x+8\right)$

$0+\log _{10}\left(x-7\right)=4-\log _{10}\left(x-7\right)+\log _{10}\left(x+8\right)+\log _{10}\left(x-7\right)$

$\log _{10}\left(x-7\right)=\log _{10}\left(x+8\right)+4$

$\log _{10}\left(x-7\right)=\log _{10}\left(x+8\right)+\log _{10}\left(10000\right)$

$x-7=\left(x+8\right)\cdot \:10000$

$\mathrm{Solve\:}\:x-7=\left(x+8\right)10000:\quad x=-\dfrac{26669}{3333}$

$\mathrm{Verifying\:Solutions}:\quad x=-\dfrac{26669}{3333}\space\mathrm{False}$

$\mathrm{No\:Solution\:for\:x\in \mathbb{R}}$

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