Answer:
You can also just find the area and times that by 4
If you want I can do that, just spam tell me and I'll figure the area out and tell u the answer in comments.
Step-by-step explanation:
Answer:
15.5 ft
Step-by-step explanation:
The geometry of the problem can be modeled by a right triangle with hypotenuse 16 ft and one side length of 4 ft. If x represents the height of the ladder on the building, then the Pythagorean theorem tells us ...
x^2 + (4 ft)^2 = (16 ft)^2
x^2 = 240 ft^2 . . . . . . subtract 16 ft^2
x ≈ 15.5 ft . . . . . . . . . . take the square root
The top of the ladder is about 15.5 ft above the ground.
Answer: X=2
Step-by-step explanation:
Assuming the function is
All logarithmic functions, despite their base, has a vertical asymptote at argument = 0.
That is not changed by the vertical stretching made by the 4 which multiplies the logarithm nor the vertical shift made by the +5.
In this case the argument is x - 2, then the vertical asymptote is:
x - 2 = 0
This is a polygon with vertices on the lattice. Let's use Pick's Theorem,
A = (1/2) B + I - 1
where A is the area, B is the number of lattice points on the boundary and I is the number of lattice points in the interior.
In addition to the 3 vertices there are 3 more boundary points on UV and 6 more on WV, none on UV, B=3+3+6=12. In the interior I count I=9 lattice points.
A = (1/2) 12 + 9 - 1 = 14
Answer: 14
Obviously they just want us to say this is a right triangle, so the legs are altitude and base,
A = (1/2) b h (1/2) |UW| |WV| = (1/2) (4) (7) = 14
That checks.
