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3 years ago

12

(x - 10) + (3x - 6) Also and why?

1 answer:

DiKsa [7]3 years ago

8 0

(x - 10) + (3x - 6)

combine like terms

x+3x -10-6

4x-16

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2 years ago

Algebra 2b need help!!

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Answer:

The answer is B, It's the only one that doesn't equal to Zero

Step-by-step explanation:

Excluded values are also called points of discontinuity. These are the values that make the denominator equal to zero and are not part of the domain

Basically the answer cannot equal to zero.

2x^2=0

2x^2/2=0/2

x^2=0

x=0

3x+3=0

3x+3-3=0-3

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3 years ago

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The clocks show when Angelica went to sleep last night and when she woke up this morning. How long did she sleep?

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4 years ago

the function y= x/tanx is ( an even, an odd, neither an even or odd) function, the function y= secx/x is (an even, an odd, neith

notka56 [123]

Answer:

If $v(x)=\frac{x}{\tan(x)}$ , then $v$ is even.

If $w(x)=\frac{\sec(x)}{x}$ , then $w$ is odd.

Step-by-step explanation:

Summary of rules/ what we need:

$f(-x)=f(x)$ implies $f$ is even.

$f(-x)=-f(x)$ implies $f$ is odd.

So in either case, we need to replace $x$ with $-x$ .

Let's begin.

First Problem:

$v(x)=\frac{x}{\tan(x)}$

Replace $x$ with $-x$ :

$v(-x)=\frac{-x}{\tan(-x)}$

$v(-x)=\frac{-x}{-\tan(x)}$ (We used $\tan(x)$ is odd; that is, $\tan(-x)=-\tan(x)$ )

$v(-x)=\frac{x}{\tan(x)}$

$v(-x)=v(x)$

This implies $v$ is an even function.

Second Problem:

$w(x)=\frac{\sec(x)}{x}$

Replace $x$ with $-x$ :

$w(-x)=\frac{\sec(-x)}{-x}$

$w(-x)=\frac{\sec(x)}{-x}$ (We used $\sec(x)$ is even; that is, $\sec(-x)=\sec(x)$ )

$w(-x)=-\frac{\sec(x)}{x}$

$w(-x)=-w(x)$

This implies $w$ is an odd function.

7 0

3 years ago