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soldier1979 [14.2K]
3 years ago
5

Hombres ilustres matemáticos en orden cronológico​

Mathematics
1 answer:
MissTica3 years ago
5 0

<em>Answer:</em>

<em>?</em>

<em>explanation: 772.malachi on insta</em>

<em>¿Qué son las matemáticas?</em>

<em></em>

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It is recommended that one fire extinguisher be available for every 6000 feet in the building write and solve an equation to det
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135,000 divided by 6000 =22.5
x = 22.5
7 0
3 years ago
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Find all real solutions of the equation. (Enter your answers as a comma-separated list.)
34kurt

Answer:

0,1

Step-by-step explanation:

x^2 − x = 0

Factor out an x

x(x-1) =0

Using the zero product property

x=0     x-1=0

Solving each equation

x=0    x-1+1 =0+1

x=0      x=1

The solutions are

x=0,1

7 0
3 years ago
Find the Taylor series for f(x) centered at the given value of a. [Assume that f has a power series expansion. Do not show that
juin [17]

Answer:

The Taylor series of f(x) around the point a, can be written as:

f(x) = f(a) + \frac{df}{dx}(a)*(x -a) + (1/2!)\frac{d^2f}{dx^2}(a)*(x - a)^2 + .....

Here we have:

f(x) = 4*cos(x)

a = 7*pi

then, let's calculate each part:

f(a) = 4*cos(7*pi) = -4

df/dx = -4*sin(x)

(df/dx)(a) = -4*sin(7*pi) = 0

(d^2f)/(dx^2) = -4*cos(x)

(d^2f)/(dx^2)(a) = -4*cos(7*pi) = 4

Here we already can see two things:

the odd derivatives will have a sin(x) function that is zero when evaluated in x = 7*pi, and we also can see that the sign will alternate between consecutive terms.

so we only will work with the even powers of the series:

f(x) = -4 + (1/2!)*4*(x - 7*pi)^2 - (1/4!)*4*(x - 7*pi)^4 + ....

So we can write it as:

f(x) = ∑fₙ

Such that the n-th term can written as:

fn = (-1)^{2n + 1}*4*(x - 7*pi)^{2n}

6 0
3 years ago
Sara is ordering t-shirts for her school. Sally's Shirt Shop charges $8.50 for each shirt and a one-time set up fee of $60. Shau
tensa zangetsu [6.8K]

Answer:

A ) 8.50x + 11 < 24x + 60

B ) 8.50x + 24 < 11x + 60

C ) 11x + 24 < 8.50x + 60

D ) 8.50x + 60 < 11x + 24

Step-by-step explanation:

8 0
3 years ago
Marine biologists have been studying the effects of acidification of the oceans on weights of male baluga whales in the Arctic O
PSYCHO15rus [73]

Answer:

c. 61.25 kg

Step-by-step explanation:

The margin of error in estimating the true mean weight of male baluga whales in the Artic Ocean.

a. 15.31 kg

b. 51.40 kg

c. 61.25 kg

d. 80.49 kg

Margin of Error Formula= z × Standard deviation/√n

95% confidence interval = 1.96

Standard deviation = 125kg

n = 16 samples

Margin of error= 1.96 × 125/√16

= 1.96 × 125/4

= 245/4

= 61.25kg

The margin of error in estimating the true mean weight of male baluga whales in the Artic Ocean is 61.25kg

6 0
3 years ago
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