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2 years ago

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the grocery store sells kumquats for $4.50 a pound and asian pears for $3.75 a pound. write an equation in standard form for the

weights of kumquats k and asian pears p that a customer could buy with $16.

1 answer:

labwork [276]2 years ago

5 0

4.5k + 3.75p = 16 <==ur equation in standard form

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Every day 10% of the liquid present in the morning in Kyle's open container will evaporate. At the end of three days, what perce

lozanna [386]

At the end of three days, $72.9$ % of the original amount of liquid remains in Kyle's container .

<u>Step-by-step explanation:</u>

Here we have , Every day 10% of the liquid present in the morning in Kyle's open container will evaporate. At the end of three days, We need to find what percent of the original amount of liquid remains in Kyle's container . Let's find out:

Let's suppose initially we have 100% of liquid present so ,

<u>At day 1:</u>

10% of the liquid present(100%) in the morning in Kyle's open container will evaporate , So left is :

⇒ $100- \frac{100(10)}{100}$

⇒ $100-10$

⇒ $90$ %

<u>At day 2:</u>

10% of the liquid present(90%) in the morning in Kyle's open container will evaporate , So left is :

⇒ $90- \frac{90(10)}{100}$

⇒ $90-9$

⇒ $81$ %

<u>At day 3:</u>

10% of the liquid present(81%) in the morning in Kyle's open container will evaporate , So left is :

⇒ $81- \frac{81(10)}{100}$

⇒ $81-8.1$

⇒ $72.9$ %

Therefore , At the end of three days, $72.9$ % of the original amount of liquid remains in Kyle's container .

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2 years ago

The mean survivial time after diagnosis for a certain disease is 15 years with a standard deviation of 5 years. Based on a parti

frutty [35]

Answer:

The time the patient expected to survive after diagnosis is 29 years.

Step-by-step explanation:

It is provided that the mean survival time after diagnosis for a certain disease is 15 years with a standard deviation of 5 years.

That is,

$\mu=15\\\sigma=5$

An individual's predicted survival time is <em>a</em> = 2.8 standard deviations beyond the mean.

Compute the time the patient expected to survive after diagnosis as follows:

$X=\mu+a\sigma$

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Thus, the time the patient expected to survive after diagnosis is 29 years.

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You would shade in 135 of the squares in the grid(s)

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