A farmer sells carrots and squash. A customer buys 1 pound of carrots and 1.5 ponds of squash for $7.00. Another customer buys 4
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<u>ANSWER: </u>
If a ball is thrown into the air with a velocity of 34 feet per second, then velocity of the ball after 1 second is 2 feet per second
<u>SOLUTION: </u>
Given, a ball is thrown into the air with a velocity of 34 feet per second
Initial velocity (u) = 34 feet per second
And also given a relation between displacement and time = --- eqn 1
We need to find the velocity when t = 1 ; v = ?
We know that, v = u + at and
where v is instantaneous velocity and u is initial velocity
a is acceleration
t is time interval
s is displacement
using the displacement and time relation eqn (1) we get
Now, when t = 1, displacement s = 34(1) – 16(1)
here, -ve sign indicates that object is in deceleration . so acceleration is -32 ft/s
now put a value in v = u + at
v = 34 + (-32)(1)
v = 34 – 32
v = 2 ft/s
Hence, velocity of the ball after 1 second is 2 ft/s
Given the table below representing the number of hours of television nine Math II class students watched the night before a big test on
triangles
along with the grades they each earned on that test.
![\begin{center} \begin{tabular} {|c|c|} Hours Spent Watching TV & Grade on Test (out of 100) \\ [1ex] 4 & 71 \\ 2 & 81 \\ 4 & 62 \\ 1 & 86 \\ 3 & 77 \\ 1 & 93 \\ 2 & 84 \\ 3 & 80 \\ 2 & 85 \end{tabular} \end{center}](https://tex.z-dn.net/?f=%5Cbegin%7Bcenter%7D%0A%5Cbegin%7Btabular%7D%0A%7B%7Cc%7Cc%7C%7D%0AHours%20Spent%20Watching%20TV%20%26%20Grade%20on%20Test%20%28out%20of%20100%29%20%20%5C%5C%20%5B1ex%5D%0A4%20%26%2071%20%5C%5C%20%0A2%20%26%2081%20%5C%5C%20%0A4%20%26%2062%20%5C%5C%20%0A1%20%26%2086%20%5C%5C%20%0A3%20%26%2077%20%5C%5C%20%0A1%20%26%2093%20%5C%5C%20%0A2%20%26%2084%20%5C%5C%20%0A3%20%26%2080%20%5C%5C%20%0A2%20%26%2085%0A%5Cend%7Btabular%7D%0A%5Cend%7Bcenter%7D)
Let the number the number of hours of television each of the students watched the night before the test be x while the grades they each earned on that test be y.
We use the following table to find the equation of the line of best fit of the regression analysis of the data.
![\begin{center} \begin{tabular} {|c|c|c|c|} x & y & x^2 & xy \\ [1ex] 4 & 71 & 16 & 284 \\ 2 & 81 & 4 & 162 \\ 4 & 62 & 16 & 248 \\ 1 & 86 & 1 & 86 \\ 3 & 77 & 9 & 231 \\ 1 & 93 & 1 & 93 \\ 2 & 84 & 4 & 168 \\ 3 & 80 & 9 & 240 \\ 2 & 85 & 4 & 170 \\ [1ex]\Sigma x=22 & \Sigma y=719 & \Sigma x^2=64 & \Sigma xy=1,682 \end{tabular} \end{center}](https://tex.z-dn.net/?f=%5Cbegin%7Bcenter%7D%20%5Cbegin%7Btabular%7D%20%7B%7Cc%7Cc%7Cc%7Cc%7C%7D%20x%20%26%20y%20%26%20x%5E2%20%26%20xy%20%5C%5C%20%5B1ex%5D%204%20%26%2071%20%26%2016%20%26%20284%20%5C%5C%202%20%26%2081%20%26%204%20%26%20162%20%5C%5C%204%20%26%2062%20%26%2016%20%26%20248%20%5C%5C%201%20%26%2086%20%26%201%20%26%2086%20%5C%5C%203%20%26%2077%20%26%209%20%26%20231%20%5C%5C%201%20%26%2093%20%26%201%20%26%2093%20%5C%5C%202%20%26%2084%20%26%204%20%26%20168%20%5C%5C%203%20%26%2080%20%26%209%20%26%20240%20%5C%5C%202%20%26%2085%20%26%204%20%26%20170%20%5C%5C%20%5B1ex%5D%5CSigma%20x%3D22%20%26%20%5CSigma%20y%3D719%20%26%20%5CSigma%20x%5E2%3D64%20%26%20%5CSigma%20xy%3D1%2C682%20%5Cend%7Btabular%7D%20%5Cend%7Bcenter%7D)
Recall that the equation of the line of best fit of a regression analysis is given by
where:
and
Thus, the equation of the line of best fit is given by y = 97.95 - 7.391x
<span>A student that watched 1.5 hours of TV will have a score given by
y = 97.95 - 7.391(1.5) = 97.95 - 11.0865 = 86.8635
Therefore, </span><span>a student’s score if he/she watched 1.5 hours of TV to the nearest whole number is 87.</span>
Let the number the number of hours of television each of the students watched the night before the test be x while the grades they each earned on that test be y.
We use the following table to find the equation of the line of best fit of the regression analysis of the data.
Recall that the equation of the line of best fit of a regression analysis is given by
where:
and
Thus, the equation of the line of best fit is given by y = 97.95 - 7.391x
<span>A student that watched 1.5 hours of TV will have a score given by
y = 97.95 - 7.391(1.5) = 97.95 - 11.0865 = 86.8635
Therefore, </span><span>a student’s score if he/she watched 1.5 hours of TV to the nearest whole number is 87.</span>
Answer:
Raising something to a negative exponent is just taking the reciprocal of the amount.
Step-by-step explanation:
Let's assume that you wanted to know what is.
To find it, you would take the reciprocal of the x amount. So becomes
.
This works because of the nature of exponents. Exponents represent the number of times you are multiplying a value by itself. So would be equal to a · a · a. To increase the exponent, you increase the number of times the value is multiplied by itself: To increase
to
, you would have to multiply a with
two more times (a · a · a · a · a). To decrease the exponent, you must divide the value by itself. So to decrease
to
, you would have to divide
by a 3 times.
If the exponent is 0, the value is equal to 1. But you can still decrease the exponent into negative numbers. You just divide 1 by a the desired amount of times: means that you are dividing 1 by a 3 times.
Hope this helps.