to get the equation of any straight line we only need two points off of it, hmmm let's use P and Q here and then let's set the equation in standard form, that is
standard form for a linear equation means
• all coefficients must be integers, no fractions
• only the constant on the right-hand-side
• all variables on the left-hand-side, sorted
• "x" must not have a negative coefficient
Find the slope soooo its (y2-y1/x2-x1)= -4/4 so -1 is slope
equation is y=-x+4
Answer:
6x-4y=24
Step-by-step explanation:
From the graph, there are two intersections to be found one at (4,0) and another at (0,-6)
Now,
slope,m= y1-y2/x1-x2
=0+6/4-0
=3/2
The equation of the straight line passingt through the point (4,0) is
y-y1=m(x-x1)
or, y-0=3/2 (x-4)
or, 2y=3x-12
or, 3x-2y=12
or, 2(3x-2y)=2(12) [Multiplying both sides by 2]
or, 6x-4y=24
The answers 10 because you add them all together then multiple 5 by 2
Answer:
x = -4
Step-by-step explanation:
If y is equal to-x + 2 then you can plug that into the second equation as x - 4(-x + 2) = -28 after this distribute out the -4 to get x + 4x - 8 = -28. After this combine the like terms to get 5x = -20. Then get x by itself by dividing by 5 to get x = -4.
