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Marat540 [252]
3 years ago
13

Find all possible values for the variables. complete two of the three problems

Mathematics
1 answer:
hjlf3 years ago
3 0

Answer: reeet

Step-by-step explanation:

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Please help do tmrw
iren2701 [21]

Answer:

One is 3x+2 while the other is 2x-1

Step-by-step explanation:

It is opposite to one another

the one with 3x+2 is opposite to the non given one and the one withb2x-1 is opposite

5 0
2 years ago
If a+b+c=0 for a,b,c then prove a²/bc+b²/ca+c²/ab=3.
Ierofanga [76]
According to the identity if a+b+c=0
then a3+b3+c3=3abc
a3+b3+c3/abc=3
a2*a/bc*a+b2*b/ca*b+c2*c/ab*c=3
cancel a,b,c in   all the fraction then you get
<span>a²/bc+b²/ca+c²/ab=3. 
</span>hence proved


5 0
3 years ago
Given the system of equations, match the following items. x + 2y = 7 x - 2y = -1 y determinant 2. x determinant 3. system determ
Veseljchak [2.6K]

Answer:

y determinant is 3

x determinant  is 2

system determinant is 1

8 0
3 years ago
Read 2 more answers
Please help with both and leave a small explanation! I wanna double check my answers! Also I’ll mark brainliest :)
77julia77 [94]

Answer:

1. 10m

2. 18 ft

Step-by-step explanation:

These are just ratios. They are both essentially doubling

7 0
3 years ago
Read 2 more answers
Jared has 12 more comic books than Zoe. If they have 28 comic books
ZanzabumX [31]

Answer:

20 comic books

Step-by-step explanation:

Let us first <u>set up a variable</u>, x, for the number of books that Zoe has. If Jared has 12 more comics than Zoe, he would have x+12 books.

Given that Zoe and Jared have a total of 28 comic books, let us write an <u>equation</u> and solve for x:

x+x+12=28\\2x+12=28

Now that we have a <u>simplified</u> version of the equation, let us solve for x by <u>isolating the variable</u> on the left side:

2x=28-12\\2x=16\\x=8

We now know that x=8, and also that Jared has x+12 books. To find the number of comic books Jared has, let us <u>add</u> 12 to x:

x+12=\\8+12=\\20\\

Therefore, Jared has 20 comic books.

<em>I hope this helps! Please let me know if you have any further questions :)</em>

4 0
3 years ago
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