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Georgia [21]
3 years ago
7

What is the approximate distance between points (-7,2) and (11,-5)?

Mathematics
1 answer:
nataly862011 [7]3 years ago
5 0

The approximate distance between points (-7,2) and (11,-5) is

=√[11-(-7)]²+[(-5-2)]²

=√(18)²+(-7)²

=√324+49

=√373

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Suzy has some stickers and a sticker album. if she pastes 7 stickers on each page, she will need 21 more stickers. If she pastes
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15 pages

Step-by-step explanation:

let x be the number of pages

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8 0
3 years ago
Jason has to finish the 40% of an art project that Has taken him a total of two hours so far if he continues to work at the same
Nitella [24]

Answer:

in total 5 hours

Using proportions part/whole, percent/100 you put the 40 in the percent spot and the 2 in the part spot cross multiply and divide so 2 x 100 divided by 40 and you get 5

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3 years ago
Solve the equation. 5(x + 4) = 70 18 14 –6 10
skelet666 [1.2K]

Assignment: \bold{Solve \ Equation: \ 5\left(x+4\right)=70}

<><><><><>

Answer: \boxed{\bold{x=10}}

<><><><><>

Explanation: \downarrow\downarrow\downarrow

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[ Step One ] Divide Both Sides By 5

\bold{\frac{5\left(x+4\right)}{5}=\frac{70}{5}}

[ Step Two ] Simplify

\bold{x+4=14}

[ Step Three ] Subtract 4 From Both Sides

\bold{x+4-4=14-4}

[ Step Four ] Simplify

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\bold{\rightarrow Mordancy \leftarrow}

6 0
3 years ago
the length of a rectangle is 1 cm more than twice it's width. of area of the rectangle is 21 cm^2 then what are the dimensions?
larisa86 [58]
You are given a rectangle and are told that the length is 1 cm more than twice the width of the rectangle.  The area of the rect. is also given, and is 21 cm^2.

Find the length and width.  To do this, represent the length by y and the width by x.  Then "1 cm more than twice the width" comes out to y=2x+1 (cm).

Since the area of a rect. is equal to the product of its length and width, 

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Solve this quadratic equation for x.  Recall that x (in cm) will represent the width of the rect., and y=2x+1 (in cm) will repr. the length.
8 0
3 years ago
Sally is having a problem with her puppy leaving the yard so she decides to build a new fence. The length of the yard is 7 feet
bezimeni [28]

The length = 6W + 7. 2L + 2W = 70. This is a system of equations. To get L by itself in the second problem, -2W from both sides to get 2L = 70 - 2W. Divide by 2 to get L = 35 - W. Now put them together. 6W +7 = 35 - W. Add W to both sides to get 7W + 7 = 35. Subtract 7 from both sides to get 7W = 28. Divide 7 to both sides to get W = 4. Now replace W with 4. 6(4) + 7 = L. 24 + 7 = 31. The length is 31. To check, do the second equation. 2(31) + 2(4) = 62 + 8 = 70. Your answer is 31.

3 0
3 years ago
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