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4 years ago

Which recursive formula can be used to represent the sequence 2,6,10,14,18,...??? Help ASAP!!!!!

Mathematics

2 answers:

Gemiola [76]4 years ago

8 0

Answer:

The first term = 2

a1 = 2

a_n=a_{n-1}+4

Step-by-step explanation:

WINSTONCH [101]4 years ago

3 0

We have the sequence 2, 6, 10, 14, 18, ... Always 4 being added, so we can say:

The first term is 2. The added is 4, so,

a1 = 2

$a_n=a_{n-1}+4$

Prove:

$a_2=a_{2-1}+4 => a_2=a_1+4=>a_2=2+4=6$

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Question 13. Please

Sonbull [250]

Answer:

Step-by-step explanation:

Δ OPG is right with hypotenuse OG being the radius of the circle

Using Pythagoras' identity in the right triangle

OG² = OP² + PG²

[ PG = 11 , since OP is the perpendicular bisector of FG ]

OG² = 8² + 11² = 64 + 121 = 185

Δ OQS is right with hypotenuse OS being the radius

Using Pythagoras' identity

OS² = QS² + OQ² , that is

185 = 13² + x²

185 = 169 + x² ( subtract 169 from both sides )

16 = x² ( take the square root of both sides )

4 = x → d

8 0

3 years ago

If you wanted to tip the waiter 29% of a check of $58 how much tip would you leave

sergey [27]

16.82 is the correct answer
29%* 58= 16.82

7 0

3 years ago

a boat costs $16,600 and decreases in value by 14% per year. how much will the boat be worth after 11 years ?

MAVERICK [17]

Answer:

In the end, $16600 has turned into $3159.30.

Step-by-step explanation:

Notice that at each compounding step above, the new principal can be found by applying this formula:

NewPrincipal = CurrentPrincipal × (1 + r)

where r is your interest rate at the time of compounding, in this case -14% (or -0.14 in the calculations).

As an example, look at the first compounding step:

$14276.00=$16600.00 × (1 + -0.14).

And the second:

$12277.36=$14276.00 × (1 + -0.14).

In fact, the whole compound interest amount boils down to multiplying (1+r), or (1+-0.14), times your original principal 11 times (11 years at 1 compouding(s) per year).

Mathematically though, this is equivalent to multiplying your orginial principal by the factor (1+-0.14)11.

If we do this, we'll get that your final amount is:

$16600.00 × (1+-0.14)11=$3159.30

8 0

3 years ago

A point is plotted on a number line at 3.7. A second point is plotted at -5.5. What is the length of the line segment joining th

weqwewe [10]

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5 0

3 years ago

The Half-life of a certain substance is 20 mins. You start with 45 mg of the substance

DochEvi [55]

a. Remaining amount after t minutes = 45 * $(1/2)^{\frac{t}{20 }$

b. 0.010986 mg

c. 109.84 minutes

Step-by-step explanation:

Step 1:

The decay of the substance is exponential. It is given that half life is 20 minutes and initially we start with 45 mg. So in 20 minutes we will have remaining amount 45/2, in 40 minutes remaining amount will be 45/4 etc.

This can be modeled by the equation:

Remaining amount after t minutes = Original amount * $(1/2)^{\frac{t}{t_{1/2} }$

where $t_{\frac{1}{2}}$ represents the half life.

The half life for this substance is 20 minutes.

Hence the Remaining amount after t minutes = 45 * $(1/2)^{\frac{t}{20 }$

Step 2:

We need to calculate the amount remaining after 4 hours (240 minutes).

Substituting t = 240 in above equation we get

Amount remaining after 4 hours = 45 * $(1/2)^{\frac{240}{20 }$ = 0.010986 mg

Step 3:

We need to calculate the time taken when 1 milligram is left. Substituting in the equation we get

1 = 45 * $(1/2)^{\frac{t}{20 }$

Taking log on both sides we get

t = $\frac{20 ln (1/45)}{ln 1/2}$ = 109.84 minutes

Time taken for 1 mg of the substance to be left = 109.84 minutes

Step 4 :

Answer :

a. Remaining amount after t minutes = 45 * $(1/2)^{\frac{t}{20 }$

b. 0.010986 mg

c. 109.84 minutes

7 0

4 years ago