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3 years ago

A 10 gram ball is rolling at 3 m/s. The ball has __________ energy. Calculate it.

Mathematics

2 answers:

sladkih [1.3K]3 years ago

3 0

Answer:

kinetic

Step-by-step explanation:mark brainliest plzzzzzzzzzz

sammy [17]3 years ago

3 0

Aswer: Kinetic is the answer

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Car A began a journey from a point at 9 am, traveling at 30 mph. At 10 am car B started traveling from the same point at 40 mph

mafiozo [28]

At 10 am, Car A is at 30 miles.

Then at 11 am, Car A is at 60 miles and Car B is at 40 miles

At 12 am, Car A is at 90 miles and Car B is at 80 miles

At 1 pm, Car A and B are tied for 120 miles

The very second after Car B passes Car A

Answer: 1:01 pm Car B Passes Car A

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3 years ago

Write and solve an equation based off the verbal phrase. 10 less than half a number is 27

Naily [24]

Do 27 - 10 = 17∠ 10
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3 years ago

Which statement could the expression n + 1 represent? one point greater than the last test grade the difference of Gina's score

sukhopar [10]

Answer:

A. One point greater than the last test grade.

Step-by-step explanation:

One point greater than the last test grade can be written as an expression:n + 1

The difference of Gina’s score and one can be written as an expression:

n - 1

The total cost less one dollar can be written as an expression: n - 1

One minute less than Mickey’s previous time can be written as an expression: n - 1

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3 years ago

Read 2 more answers

An isosceles trapezoid ABCD with height 2 units has all its vertices on the parabola y=a(x+1)(x−5). What is the value of a, if p

horrorfan [7]

Answer:

a = -0.3575

Step-by-step explanation:

The points A and D lie on the x-axis, this means that they are the x-intercepts of the parabola, and therefore we can find their location.

The points A and B are located where

$y=a(x+1)(x-5)=0$

This gives

$x=-1$

$y=5$

Now given the coordinates of A, we are in position to find the coordinates of the point B. Point B must have y coordinate of y=2 (because the base of the trapezoid is at y=0), and the x coordinate of B, looking at the figure, must be x coordinate of A plus horizontal distance between A and B, i.e

$B_x=A_x+\frac{2}{tan(60)} =-1+\frac{2\sqrt{3} }{3}$