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Likurg_2 [28]
3 years ago
6

what solid 3D object is produced by rotating the triangle about line m with a height of 8 and radius 4

Mathematics
1 answer:
Oksi-84 [34.3K]3 years ago
3 0

Answer:

The diagram of the question is missing, I found a matching diagram, and it is attached to this answer

The 3D object produced is a cone with height 8 and diameter 8 (radius 4)

Step-by-step explanation:

A 3 dimensional solid figure can be formed when a 2 dimensional object is rotated about a line without displacing the object.

when the object in the diagram is rotated about line m, the rotation forms an object with a circular base of diameter 8 units (radius 4) from the base of the triangle and height 8 units, and the 3D object formed is called a cone.

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Answer:

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Step-by-step explanation:

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A segment is dilated, and the resulting segment is shorter than the original.
kati45 [8]

Answer:

3/8 and 1/5

Step-by-step explanation:

If the scale factor is 1 then it stays the same. If it's larger than 1 then is gets larger, so the fractions, which are smaller than 1, would make it shorter.

hope this helped :)

7 0
4 years ago
The probability of a basketball player hitting a foul shot is 1/3. How many shots would you expect her to make in 90 attempts?
wariber [46]

Answer:

60

Step-by-step explanation:

1/3 of all attempts expected to be foul shots

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3 years ago
The height of a small rock falling from the top of a 124-ft-tall building with an initial downward velocity of –30 ft/sec is mod
Contact [7]

Answer:

Option 3.

Step-by-step explanation:

The given function is

h(t)=-16t^2-30t+124

where, h(t) is the height of a small rock falling from the top of a 124-ft-tall building and t is the time in seconds.

It is a downward parabola.

Equate the function equal to 0, to find the time at which the rock touch the ground.

-16t^2-30t+124=0

If ax^2+bx+c=0, the according to the quadratic formula

x=\dfrac{-b\pm \sqrt{b^2-4ac}}{2a}

Using quadratic formula, we get

t=\dfrac{-(-30)\pm \sqrt{(-30)^2-4(124)(-16)}}{2(-16)}

t=\dfrac{30+\sqrt{(-30)^2-4(124)(-16)}}{2(-16)},\dfrac{30-\sqrt{(-30)^2-4(124)(-16)}}{2(-16)}

t=-3.875, 2

Time cannot be negative. So, the rock remain in the air in the interval 0 < t < 2.

Therefore, the correct option is 3.

6 0
3 years ago
The distance between -2 1/2 - (-3)
Ierofanga [76]

The distance between -2 1/2 - (-3)​

-2 1/2 + 3

1/2

______________________

Answer

1/2

3 0
1 year ago
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