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3 years ago

HELP, please!! What is the area of a trapezoid ABC?

Mathematics

2 answers:

MrRa [10]3 years ago

5 0

Answer:

<h2>26 feet squared</h2>

Step-by-step explanation:

Area of trapezoid:

$\frac{1}{2} \times \: sum \: of \: parallel \: sides \: \times height$

plugging the values:

$\frac{1}{2} \times (21 + 5) \times 2$

Calculate the sum

$\frac{1}{2} \times 26 \times 2$

Reduce the numbers with G.C.F 2

$13 \times 2$

Calculate the product

$26$ feet squared.

Hope this helps...

Best regards!

Shtirlitz [24]3 years ago

3 0

It’s c just to let you know I have done this before

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Find the area of the region under the graph of f on [a, b].<br> f(x) = x2 − 8x + 17; [−1, 2]

Harman [31]

Answer:

The area is 42 area units.

Step-by-step explanation:

The area of a function f(x) on an interval [a,b] is given by:

$A = \int\limits^a_b {f(x)} \, dx$

Applying to this question:

$A = \int\limits^-1_2 {x^2 - 8x + 17} \, dx$

Then

$F(x) = \frac{x^{3}}{3} - 4x^{2} + 17x$

$A = F(2) - F(-1)$

$F(2) = frac{2^{3}}{3} - 4*2^{2} + 17*2 = \frac{8}{3} + 18 = \frac{8 + 3*18}{3} = \frac{62}[3}$

$F(-1) = frac{(-1)^{3}}{3} - 4*(-1)^{2} + 17*(-1) = -\frac{1}{3} - 21 = \frac{-1 - 21*3}{3} = -\frac{64}[3}$

$A = F(2) - F(-1) = \frac{62}[3} - (-\frac{64}[3}) = \frac{62+64}{3} = 42$

The area is 42 area units.

5 0

3 years ago

two blocks of wood are shaped as right rectangle prisms the smaller block has a length of 9 cm a width of 3 cm and a height of 7

dolphi86 [110]

Answer:

1,512 cm³

Step-by-step explanation:

The general formula for the volume of a prism is:

V= Bh, where B = the area of the base and h = height of the prism

Given the dimensions of the smaller block as 9cm x 3cm x 7cm, then the dimensions of the larger block (double the dimensions of the smaller block) must be 18cm x 6cm x 14cm. Using these measurements:

V = (18)(6)(14) = 1,512 cm³

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3 years ago

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iogann1982 [59]

${\qquad\qquad\huge\underline{{\sf Answer}}}$

The given figure shows a vertical hyperbola with its centre at origin, and as we observe the figure, we can conclude that :

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$\qquad \sf \dashrightarrow \: 2b = 12$

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$\qquad \sf \dashrightarrow \: 2a = 8$

$\qquad \sf \dashrightarrow \: a = 4$

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$\qquad \sf \dashrightarrow \: \cfrac{ {y}^{2} }{ {b}^{2} } - \cfrac{ {x}^{2} }{ {a}^{2} } = 1$

plug in the values ~

$\qquad \sf \dashrightarrow \: \cfrac{ {y}^{2} }{ {6}^{2} } - \cfrac{ {x}^{2} }{ {4}^{2} } = 1$

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2 years ago

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dezoksy [38]

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Step-by-step explanation:

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3 years ago

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Sholpan [36]

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3 years ago