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3 years ago

Turn 3.7105425043 into a fraction

Mathematics

1 answer:

vova2212 [387]3 years ago

3 0

Answer:

37105425043/10000000000

Step-by-step explanation:

Remember that multiplying by 10 moves the decimal to the right. So, if you multiply 3.7105425043 by 10, you get 37.105425043. So, another way to right this number would be 37.105425043/10. That doesn't quite work because the numerator, 37.105425043, is still not a whole number.

But, if keep multiplying numerator and denominator by 10, you will eventually get 37105425043/10000000000; now, you just need to simplfy.

Because the denominator, 10000000000, has only 2's and 5's as factors (because it is a power of 10), and the numerator does not have any factors of 2 or 5 (because it is not even and does not end in 5 or 0), no simplication is possible.

Thus, the answer is 37105425043/10000000000

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Write the explicit rule for the arithmetic sequence

blagie [28]

Given that:
a1=27, an=(an-1)+4
the second term will be:
a2=a1+4
a2=27+4=31
The explicit formula for arithmetic sequence is given by:
an=a+(n-1)d
where:
a= first term
d=common difference
n=nth term
from the information given:
a=27
d=31-27=4
thus the explicit formula will be:
an=27+(n-1)4
an=27+4n-4
an=23+4n

Answer: an=23+4n

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3 years ago

What is the constant(K)?

s344n2d4d5 [400]

Answer:

a (5)

Step-by-step explanation:

The constant is the same as y/x in a proportional relationship

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3 years ago

Find the absolute maximum and minimum values of f(x, y) = x+y+ p 1 − x 2 − y 2 on the quarter disc {(x, y) | x ≥ 0, y ≥ 0, x2 +

Andreas93 [3]

Answer:

absolute max: f(x,y)=1/2+p1 ; at P(1/2,1/2)

absolute min: f(x,y)=p1 ; at U(0,0), V(1,0) and W(0,1)

Step-by-step explanation:

In order to find the absolute max and min, we need to analyse the region inside the quarter disc and the region at the limit of the disc:

Region inside the quarter disc:

There could be Minimums and Maximums, if:

∇f(x,y)=(0,0) (gradient)

we develop:

(1-2x, 1-2y)=(0,0)

x=1/2

y=1/2

Critic point P(1/2,1/2) is inside the quarter disc.

f(P)=1/2+1/2+p1-1/4-1/4=1/2+p1

f(0,0)=p1

We see that:

f(P)>f(0,0), then P(1/2,1/2) is a maximum relative

Region at the limit of the disc:

We use the Method of Lagrange Multipliers, when we need to find a max o min from a f(x,y) subject to a constraint g(x,y); g(x,y)=K (constant). In our case the constraint are the curves of the quarter disc:

g1(x, y)=x^2+y^2=1

g2(x, y)=x=0

g3(x, y)=y=0

We can obtain the critical points (maximums and minimums) subject to the constraint by solving the system of equations:

∇f(x,y)=λ∇g(x,y) ; (gradient)

g(x,y)=K

Analyse in g2:

x=0;

1-2y=0;

y=1/2

Q(0,1/2) critical point

f(Q)=1/4+p1

We do the same reflexion as for P. Q is a maximum relative

Analyse in g3:

y=0;

1-2x=0;

x=1/2

R(1/2,0) critical point

f(R)=1/4+p1

We do the same reflexion as for P. R is a maximum relative

Analyse in g1:

(1-2x, 1-2y)=λ(2x,2y)

x^2+y^2=1

Developing:

x=1/(2λ+2)

y=1/(2λ+2)

x^2+y^2=1

So:

(1/(2λ+2))^2+(1/(2λ+2))^2=1

$\lambda_{1}=\sqrt{1/2}*-1 =-0.29$

$\lambda_{2}=-\sqrt{1/2}*-1 =-1.71$

$\lambda_{2}$ give us (x,y) values negatives, outside the region, so we do not take it in account

For $\lambda_{1}$ : S(x,y)=(0.70, 070)

and

f(S)=0.70+0.70+p1-0.70^2-0.70^2=0.42+p1

We do the same reflexion as for P. S is a maximum relative

Points limits between g1, g2 y g3

we need also to analyse the points limits between g1, g2 y g3, that means U(0,0), V(1,0), W(0,1)

f(U)=p1

f(V)=p1

f(W)=p1

We can see that this 3 points are minimums relatives.

Conclusion:

We compare all the critical points P,Q,R,S,T,U,V,W an their respective values f(x,y). We find that:

absolute max: f(x,y)=1/2+p1 ; at P(1/2,1/2)

absolute min: f(x,y)=p1 ; at U(0,0), V(1,0) and W(0,1)

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3 years ago

Write a whole number that rounds to 10,000 if we are rounding to the nearest ten thousand

Inessa [10]

If you were to round it, a possible answer could be 9,997

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3 years ago

What is the least common denominator of 5\6 and 3/8

almond37 [142]

Answer:

Step-by-step explanation:

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3 years ago