Answer: Option (a) is correct.
Explanation:
Molecules of sugar given = 
According to Avogadro's number it is known that 1 mole contains
.
Therefore, calculate the moles of sugar present in the sample as follows.
Number of moles = 
= 0.25 mol
Thus, the moles of sugar present in the sample is 0.25 mol.
Answer:
Hey mate, here is your answer. Hope it helps you.
Explanation:
The balanced equation is 2Na+2H2O———-> 2NaOH +H2.
Answer:
-Reversal of the resting potential due to influx of sodium ions
-Mechanism that restores the resting membrane voltage and intracellular ionic concentrations
-Period during which potassium ions are diffusing out of the neuron because of a change in membrane permeability
-A brief reversal of membrane potential that travels along the axon
Explanation:
An action potential is a situation where the membrane potential is briefly reversed from -70mV to +30 mV
There are three steps of the moving action potential, including;
1) The depolarization step, where the membrane resting potential is reversed by the rush of sodium ions into a neuron
2) The repolarization, due to the closing of the voltage-gated sodium channels and the opening of the potassium channels, which is a mechanism that restores the membrane's resting voltage and the ionic concentration in the cell
3) Hyperpolarization, where due to some open potassium channels, there is an increased potassium permeability, and excessive efflux of potassium ions take place, which results in a dip in the membrane potential
4) The above three phases describe the phase of the action potential which is the brief reversal of membrane potential that travels along the axon
Answer:
Molarity = 0.01 M
Explanation:
Molarity is used to measure the concentration of a solution. It will be same for the whole solution or a small amount of solution if the solution is homogeneous.
So, <u>Molarity of 200 mL of solution = Molarity of 50 mL of solution</u>


given mass of aspirin = 360 mg = 0.36 g
molar mass of aspirin = 180 g
Volume of solution = 200 mL = 0.2 L


Therefore, Molarity = 0.01 M
Answer:
b. 
Explanation:
Hello there!
In this case, given the ionization reaction of HClO as weak acid:

We can write the equilibrium expression as shown below:
![Ka=3.5x10^{-8}=\frac{[H^+][ClO^-]}{[HClO]}](https://tex.z-dn.net/?f=Ka%3D3.5x10%5E%7B-8%7D%3D%5Cfrac%7B%5BH%5E%2B%5D%5BClO%5E-%5D%7D%7B%5BHClO%5D%7D)
In such a way, via the definition of x as the reaction extent, we can write:
![3.5x10^{-8}=\frac{x^2}{[HClO]}](https://tex.z-dn.net/?f=3.5x10%5E%7B-8%7D%3D%5Cfrac%7Bx%5E2%7D%7B%5BHClO%5D%7D)
As long as Ka<<<<1 so that the x on the bottom can be neglected. Thus, we solve for x as shown below:

And finally the percent dissociation:
![\% diss=\frac{x}{[HClO]} *100\%\\\\\% diss=\frac{7.94x10^{-5}M}{0.18}*100\% \\\\\% diss =0.044\%=4.4x10^{-2}\%](https://tex.z-dn.net/?f=%5C%25%20diss%3D%5Cfrac%7Bx%7D%7B%5BHClO%5D%7D%20%2A100%5C%25%5C%5C%5C%5C%5C%25%20diss%3D%5Cfrac%7B7.94x10%5E%7B-5%7DM%7D%7B0.18%7D%2A100%5C%25%20%5C%5C%5C%5C%5C%25%20diss%20%3D0.044%5C%25%3D4.4x10%5E%7B-2%7D%5C%25)
Which is choice b.
Best regards!