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polet [3.4K]
3 years ago
6

Which factors would negatively impact the bodies digestive system

Chemistry
1 answer:
swat323 years ago
3 0
<span><span>Sugar – it is heating, sticky and toxic to the body in big doses

</span><span>Lack of sleep – your body needs adequate rest to rejuvenate all organs so they can perform their intended roles

</span>Over-eating – this can send your body into shutdown mode and put excess stress on your organs

<span>Alcohol – both poisonous and toxic to the body, too much alcohol damages the body internally which is evident externally</span>

Cold food and drinks – can create stagnation in the digestive system, slowing down the digestive process considerably

<span>Emotions – anger/upset/frustration – all will affect one or more of your organs. Try and control what you can and let go of what you can’t

</span>Processed foods – they contain foreign properties that are literally indigestible by the human body

Pandadol/nuerofen – contain chemicals that will alleviate pains and complaints temporarily, yet will leave a trail of destruction. Try natural remedies instead

Anti-biotics – whilst they kill bacteria and bugs – they also kill your insides! Follow up a round of anti-biotics with some gut nourishing foods

<span>Over-exercise – will deplete your Qi and deplete your digestive strength. Exercise is fantastic in decent doses – not extremes. Are there issues in your life that you are avoiding and using exercise as a distraction from?

I only listed 10 examples for you because you didn't put any more detail on a specific number or answer.
</span></span>
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Answer: Thus 0.724 mol of CaCN_2 are needed to obtain 18.6 g of NH_3

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\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}    

\text{Moles of} NH_3=\frac{18.6g}{17g/mol}=1.09moles

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According to stoichiometry :

2 moles of NH_3 are produced by = 1 mole of CaCN_2

Thus 1.09 moles of NH_3 will be produced by =\frac{1}{2}\times 1.09=0.545moles  of CaCN_2

But as yield of reaction is 75.6 %, the amount of CaCN_2 needed is =\frac{0.545}{75.6}\times 100=0.724

Thus 0.724 mol of CaCN_2 are needed to obtain 18.6 g of NH_3

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