See the picture attached.
We know:
NM // XZ
NY = transversal line
∠YXZ ≡ ∠YNM
1) <span>
We know that ∠XYZ is congruent to ∠NYM by the reflexive property.</span>
The reflexive property states that any shape is congruent to itself.
∠NYM is just a different way to call ∠XYZ using different vertexes, but the sides composing the two angles are the same.
Hence, ∠XYZ ≡ <span>∠NYM</span> by the reflexive property.
2) Δ<span>
XYZ is similar to ΔNYM by the AA (angle-angle) similarity theoremThe AA similarity theorem states that if two triangles have a pair of corresponding angles congruent, then the two triangles are similar.
Consider </span>Δ<span>XYZ and ΔNYM:
</span>∠YXZ ≡ <span>∠YNM
</span>∠XYZ ≡ ∠NYM
Hence, ΔXYZ is similar to ΔNYM by the AA similarity theorem.
Answer:
0
Step-by-step explanation:
(sin(2n) − 1) / (sin n − cos n)
-(1 − sin(2n)) / (sin n − cos n)
-(1 − 2 sin n cos n) / (sin n − cos n)
-(sin² n − 2 sin n cos n + cos² n) / (sin n − cos n)
-(sin n − cos n)² / (sin n − cos n)
-(sin n − cos n)
cos n − sin n
Limit as n approaches π/4 is 0.
Answer:
It's D or 1/7^2

Step-by-step explanation:
They both equal 1/49
The simplification form of the provided expression is 2x²y⁴ option first is correct.
<h3>What is an expression?</h3>
It is defined as the combination of constants and variables with mathematical operators.
We have an expression:
![= \rm \sqrt[3]{8x^6y^{12}}](https://tex.z-dn.net/?f=%3D%20%5Crm%20%5Csqrt%5B3%5D%7B8x%5E6y%5E%7B12%7D%7D)
![\rm =\sqrt[3]{8}\sqrt[3]{x^6}\sqrt[3]{y^{12}}](https://tex.z-dn.net/?f=%5Crm%20%3D%5Csqrt%5B3%5D%7B8%7D%5Csqrt%5B3%5D%7Bx%5E6%7D%5Csqrt%5B3%5D%7By%5E%7B12%7D%7D)
![\rm \rm = \rm 2\sqrt[3]{x^6}\sqrt[3]{y^{12}}](https://tex.z-dn.net/?f=%5Crm%20%5Crm%20%3D%20%5Crm%202%5Csqrt%5B3%5D%7Bx%5E6%7D%5Csqrt%5B3%5D%7By%5E%7B12%7D%7D)
![\rm =2x^2\sqrt[3]{y^{12}}](https://tex.z-dn.net/?f=%5Crm%20%3D2x%5E2%5Csqrt%5B3%5D%7By%5E%7B12%7D%7D)

Thus, the simplification form of the provided expression is 2x²y⁴ option first is correct.
Learn more about the expression here:
brainly.com/question/14083225
#SPJ1
<h3>
<u>Required</u><u> Answer</u><u>:</u><u>-</u></h3>
This is an right angle ∆ and the side lengths containing a right angle are 9 and 11.
By Pythagoras theoram,

where p is the perpendicular, b is the base and h is the hypotenuse.
Plugging the values,

Then,


<h3>
<u>Hence:</u><u>-</u></h3>
The x of the right angled ∆ = <u>1</u><u>4</u><u>.</u><u>1</u><u>2</u>