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3 years ago

7

Evaluate each expression

1 answer:

Alla [95]3 years ago

7 0

Answer:

B. 13

work:

9^1/2+√25+8÷2+3²

(3²)^1/2+5-4+9

3+5-4+9

C.4/5

work

1/2*3/5*(2^3-6)+1/5

1/2*3/5*(8-6)+1/5

1/2*3/5*2+1/5

3/5+1/5

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lakkis [162]

Answer:

If she returns the skis at 3 p.m. she would pay $25. IM NOT SURE ABOUT 3:05 PM

Step-by-step explanation:

Start on the hours rented side. If she rents them at noon you would be at zero. Move to the 3 (in between 2 and 4) then if you go up it hits $25 on the rental cost side.

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Use the distributive property to remove the parenthese:<br> (-2+5u+v) (-8)

aleksandrvk [35]

Answer:

16 - 40u - 8v

Step-by-step explanation:

(- 2 + 5u + v)(- 8) ← multiply each term in the parenthesis by - 8

= 16 - 40u - 8v

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3 years ago

The difference between a number and seven is less than or equal to -3.

ikadub [295]

Answer:

n ≤ 4

Step-by-step explanation:

"The difference between a number and seven is less than or equal to -3" translates into n - 7 ≤ -3. To solve, isolate the variable n.

n - 7 ≤ -3

n ≤ -3 + 7

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3 years ago

Alex had 23 coins in his collection. He found 5 coins and gave Bill 8 coins. How many coins does Alex have now?

sashaice [31]

Alex has 20 coins now

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3 years ago

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Solve for x<br><br> THANK YOU

Anestetic [448]

Answer:

$x=\dfrac{-17+ \sqrt{451} }{18}, \quad x=\dfrac{-17- \sqrt{451} }{18}$

Step-by-step explanation:

$\textsf{Given equation}:$

$\dfrac{2}{3}x+\dfrac{3x}{x}=\dfrac{4x}{2}(3x+6)$

$\textsf{Cancel the common factor } x \textsf{ in }\dfrac{3x}{x}:$

$\implies \dfrac{2}{3}x+3=\dfrac{4x}{2}(3x+6)$

$\textsf{Simplify }\dfrac{4x}{2}\textsf{ by dividing the numbers}:$

$\implies \dfrac{2}{3}x+3=2x(3x+6)$

$\textsf{Apply the distributive law}\quad \:a\left(b+c\right)=ab+ac:$

$\implies \dfrac{2}{3}x+3=6x^2+12x$

$\textsf{Multiply both sides by 3 to cancel the denominator of }\dfrac{2}{3}:$

$\implies \dfrac{2}{3}x\cdot 3+3\cdot 3=6x^2\cdot 3+12x \cdot 3$

$\implies 2x+9=18x^2+36x$

$\textsf{Switch sides}:$

$\implies 18x^2+36x=2x+9$

$\textsf{Subtract }2x \textsf{ from both sides}:$

$\implies 18x^2+36x-2x=2x+9-2x$

$\implies 18x^2+34x=9$

$\textsf{Subtract 9 from both sides}:$

$\implies 18x^2+34x-9=9-9$

$\implies 18x^2+34x-9=0$

Solve using the <u>Quadratic Formula:</u>

$x=\dfrac{-b \pm \sqrt{b^2-4ac} }{2a}\quad\textsf{when }\:ax^2+bx+c=0$

Define the variables:

$\implies a=18, \quad b=34, \quad c=-9$

Substitute the defined variables into the quadratic formula and solve for x:

$\implies x=\dfrac{-34 \pm \sqrt{34^2-4(18)(-9)} }{2(18)}$

$\implies x=\dfrac{-34 \pm \sqrt{1156+648} }{36}$

$\implies x=\dfrac{-34 \pm \sqrt{1804} }{36}$

$\implies x=\dfrac{-34 \pm \sqrt{4 \cdot 451} }{36}$

$\implies x=\dfrac{-34 \pm \sqrt{4}\sqrt{451} }{36}$

$\implies x=\dfrac{-34 \pm 2\sqrt{451} }{36}$

$\implies x=\dfrac{-17 \pm \sqrt{451} }{18}$

Therefore, the solutions to the given equation are:

$x=\dfrac{-17+ \sqrt{451} }{18}, \quad x=\dfrac{-17- \sqrt{451} }{18}$

Learn more about the Quadratic Formula here:

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