B, make a table of possible values
the best way to do it is actually not listed
to have max area with minimu perimiter, try to get the sides as close measure to each other as possible
I would pick B though

By taking <span>logarithmic of base 10
∴ </span><span>

∴ x log 4 = log 64
∴

note: we don't need to write the base in case of the base =10
∴ The correct choice is
</span><span>x = log base 10 of 64, all over log base 10 of 4</span>
Answer:
56.39 nm
Step-by-step explanation:
In order to have constructive interference total optical path difference should be an integral number of wavelengths (crest and crest should be interfered). Therefore the constructive interference condition for soap film can be written as,

where λ is the wavelength of light and n is the refractive index of soap film, t is the thickness of the film, and m=0,1,2 ...
Please note that here we include an additional 1/2λ phase shift due to reflection from air-soap interface, because refractive index of latter is higher.
In order to have its longest constructive reflection at the red end (700 nm)

Here we take m=0.
Similarly for the constructive reflection at the blue end (400 nm)

Hence the thickness difference should be

I just met a friend for the first year old man who