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3 years ago

A container holds 50 electronic components, of which 10 are defective.

Mathematics

1 answer:

Gala2k [10]3 years ago

4 0

Answer:

There is some inforrmation that is missing in this question. It should read:

A container holds 50 electronic components, of which 10 are defective. If 6 components are drawn at random from the container, the probability that at least 4 are not defective is . If 8 components are drawn at random from the container, the probability that exactly 3 of them are defective is .

Answers

Part 1. 0.02

Part 2. 0.0375

Explanation

The probability is a chance of an event happening. It is calculated as;

probability = (Number of favourable outcome)/(Number of available outcome)

Part 1

6 are chosen at random. If 4 are not defective, then 2 are defective.

P(at least 4 are not defective) = 4/40 × 2/10

= 1/10 ×1/5

= 1/50

= 0.02

Part 2

8 are chosen at random. If 3 are defective, the 5 are not defective.

P(3 are defective) = 3/40 × 5/10

= 15/400

= 3/80

= 0.0375

Step-by-step explanation:

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