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3 years ago

find the value of k for which the following system of equations has a unique solutions 1 . kx +2y= 5 , 3x+y=1

Mathematics

1 answer:

lana66690 [7]3 years ago

3 0

Answer:

If you choose any value for k other than 6, that will be give you the one solution.

If k=6, you have no solutions because the lines will be parallel.

Step-by-step explanation:

We are going to put each of this in y=mx+b where m is the slope and b is the y-intercept.

kx+2y=5

Subtract kx on both sides:

2y=-kx+5

Divide both sides by 2:

y=(-k/2)x+(5/2)

The slope is -k/2 and the y-intercept is 5/2

3x+y=1

Subtract 3x on both sides:

y=-3x+1

The slope is -3 and the y-intercept is 1.

We want the system to have one solution so we want the slopes to be difference.

So we don't want (-k/2)=(-3).

Multiply both sides by -2: k=6.

We won't want k to be 6.

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When a number is increased by 7.1%, the result is 89. What is the original number to the nearest tenth?

balu736 [363]

Answer:

The original number is $83.1$

Step-by-step explanation:

Let

x -----> the original number

Remember that

$100\%+7.1\%=107.1\%=107.1/100=1.071$

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3 years ago

P is the centroid of XYZ. If XU = 57 what is PU? A. 38 B. 19 C. 28.5 D. 20

nalin [4]

Answer:

So the value of 'PU' is $19$

Step-by-step explanation:

Given,

'p' is the centroid of $\bigtriangleup XYZ$ and $XU=57$

∵ 'p' is the centroid then 'U' , 'V' and 'W' are the mid point of side 'YZ' , 'XZ' and 'XY'.

From Centroid Theorem we can write;

$XP=\frac{2}{3} \times XU$

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$XP=\frac{2}{3} \times57$

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From figure;

$XP+PU=XU$

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Plug 'XU' and 'XP' values;

$PU=57-38$

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7 0

4 years ago

Read 2 more answers

A student's tuition was $2628. A loan was obtained for 5/4 of the tuition. How much was the loan? The student's loan was fo

prohojiy [21]

Answer:

The loan amount of the tuition fee is $3285

Step-by-step explanation:

Given as :

The student's tuition fee amount = $2628

The loan amount for the fee = $\dfrac{5}{4}$ of the tuition fee

Let The loan amount = $ A

So, According to question

The loan amount for the fee = $\dfrac{5}{4}$ × tuition fee amount

A = $\dfrac{5}{4}$ × $2628

or, A = $\frac{5\times 2628}{4}$

Or, A = 5 × 657

∴ A = $3285

So, The loan amount = A = $3285

Hence The loan amount of the tuition fee is $3285 Answer

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3 years ago

Question 2 (10 points)

Alenkasestr [34]

Answer:

(k - 6)(k + 4)

Step-by-step explanation:

k^2 - 2k - 24

(k - 6)(k + 4)

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3 years ago

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in August if that was 79 centimeters tall in June of that year it grew 12 CM cm in July how many centimeters tall was it in June

shutvik [7]

Step-by-step explanation:

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3 years ago

find the value of k for which the following system of equations has a unique solutions 1 . kx +2y= 5 , 3x+y=1​

find the value of k for which the following system of equations has a unique solutions 1 . kx +2y= 5 , 3x+y=1