<span>(x+4)(x+1) = m+2x
x² + 5x + 4 − m − 2x = 0
x² + 3x + (4−m) = 0
Quadratic equation has exactly one real solution
when discriminant = 0
b² − 4ac = 0
3² − 4(1)(4−m) = 0
9 − 16 + 4m = 0
−7 + 4m = 0
4m = 7
m = 7/4
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Second problem:
Line y = 3 intersects graph of y = 4x² + x − 1 at point A and B
y-coordinates of points A and B = 3, since they are both on line y = 3. We need to find x-coordinates
4x² + x − 1 = 3
4x² + x − 4 = 0
x = (−1 ± √(1−4(4)(−4))) / 8
x = (−1±√65) / 8
AB = (−1+√65)/8 − (−1−√65)/8 = 2√65/8 = √65/4 = √(65/16)
m−n = 49</span>
I have take the answer from internet, I hope it help
Answer: 1, 2, 4, or 5
Step-by-step explanation:
The relationship in #3 is a function because all the x values are distinct, that is, none are repeated. (Y values don't matter.)
A function will not repeat any x values so if your goal is for the relationship in #4 to NOT be a function, repeat one of the x values. Any one will work.
Answer: .625 (yes he did leave enough
Step-by-step explanation: First you need to divde the fractions( or solve them) ,so 7 divided by 8 and so on Then you take subtract the paint ivan used, if it is less than half than ivan didn't leave enough for his poor sister
but there are other ways if this one is to hard
The vertical distance will be given by:
sinθ=opposite/hypotenuse
where:
θ=48°
opposite=h
hypotenuse=100 ft
thus
sin 48=h/100
hence
h=100 sin48
h=74.315 ft
Answer: 74.315 ft
Answer:
3
Step-by-step explanation:
The ratio of adult dog to puppies is 3:2
There were 12 puppies that day
Number of adult puppies can be calculated as follows
= 3/2× 12
= 3 ×6
= 18
There were 15 adult dogs in the park on Tuesday
Hence the difference can be calculated as follows
= 18-15
= 3
