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2 years ago

Help please! This is for geometry! Question below!!

Mathematics

1 answer:

labwork [276]2 years ago

4 0

1.) Circumscribed angle 2.) Minor arc 3.) Central Angle 4.) Inscribed Angle 5.)Major Arc

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Which choices are equivalent to the expression below? Check all that apply.

Fittoniya [83]

Answer:

A, D // other options are wrong.

8 0

2 years ago

Find the highest common factor of 72 and 135

andrey2020 [161]

Answer:9

Step-by-step explanation:

Find the prime factorization of 72

72 = 2 × 2 × 2 × 3 × 3

Find the prime factorization of 135

135 = 3 × 3 × 3 × 5

To find the GCF, multiply all the prime factors common to both numbers:

Therefore, GCF = 3 × 3

GCF = 9

4 0

2 years ago

Read 2 more answers

How do I count by twelfths

Korvikt [17]

12, x 1 = 12

12 x 2 =24

12 x 3 = 36

12 x 4 =48

12 x 5= 60

12 x 6 =72

12 x 7 = 84

12 x 8= 96

12 x 9= 108

12 x 10 = 120

12 x 11=132

12x 12= 144

hope this helps

8 0

2 years ago

Question 15

Travka [436]

Answer:

$9.95.

Step-by-step explanation:

Let's say that you are buying a avatars and b bats.

3a + 3b = 29.85

Divide all terms by 3.

a + b = 9.95

You will pay $9.95 if you buy one of each.

Hope this helps!

4 0

3 years ago

Solve the following quadratic by completing the square. y = x^2 - 6x+7

kozerog [31]

Answer:

$x= 3+\sqrt{2}, \quad x= 3 -\sqrt{2}$

Step-by-step explanation:

Given quadratic equation:

$y = x^2 - 6x+7$

To complete the square, begin by adding and subtracting the square of half the coefficient of the term in x:

$\implies y = x^2 - 6x+\left(\dfrac{-6}{2}\right)^2-\left(\dfrac{-6}{2}\right)^2+7$

$\implies y = x^2 - 6x+\left(-3\right)^2-\left(-3\right)^2+7$

$\implies y = x^2 - 6x+9-9+7$

Factor the perfect square trinomial:

$\implies y=(x-3)^2-9+7$

$\implies y=(x-3)^2-2$

To solve the quadratic, set it to zero and solve for x:

$\implies (x-3)^2-2=0$

$\implies (x-3)^2-2+2=0+2$

$\implies (x-3)^2=2$

$\implies \sqrt{(x-3)^2}=\sqrt{2}$

$\implies x-3= \pm\sqrt{2}$

$\implies x-3+3= 3\pm\sqrt{2}$

$\implies x= 3\pm\sqrt{2}$

Therefore, the solution to the given quadratic equation is:

$x= 3+\sqrt{2}, \quad x= 3 -\sqrt{2}$

6 0

3 months ago

Read 2 more answers