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3 years ago

What is the slope of the line that passes through the points

1 answer:

5 0

$\bf (\stackrel{x_1}{-3}~,~\stackrel{y_1}{1})\qquad (\stackrel{x_2}{7}~,~\stackrel{y_2}{-14}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{-14}-\stackrel{y1}{1}}}{\underset{run} {\underset{x_2}{7}-\underset{x_1}{(-3)}}}\implies \cfrac{-15}{7+3}\implies \cfrac{-15}{10}\implies -\cfrac{3}{2}$

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PLZ HELP

Alex

Answer:

The correct option is C ) 109.5°

Therefore,

$m\angle E=109.5\°$

Step-by-step explanation:

Given:

In Triangle DEF

d = 10

e = 18

f = 12

To Find

angle E = ?

Solution:

In Triangle DEF , Cosine Rule says

$\cos E=\dfrac{f^{2}+d^{2}-e^{2}}{2fd}$

Substituting the values we get

$\cos E=\dfrac{12^{2}+10^{2}-18^{2}}{2\times 12\times 10}$

$\cos E=\dfrac{-80}{240}=-\dfrac{1}{3}$

Therefore,

$\angle E=\cos^{-1}(-0.3333)$

$m\angle E=109.5\°$ ............As it is in Second Quadrant

Therefore,

$m\angle E=109.5\°$

4 0

3 years ago

Given y inversely proportional to x and x = 3 for y = 4, what is xify= 12?<br> 01<br> 9<br> 16

kari74 [83]

Answer:

Step-by-step explanation:

4 0

3 years ago

The time between failures of a machine has an exponential distribution with parameter l. Suppose that the prior distribution for

ololo11 [35]

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6 0

3 years ago

Cindy claims that 4^x/12^x = 1/3<br> What is a single-digit whole number that supports her claim?

Lana71 [14]

Answer:

x=1

Step-by-step explanation:

6 0

3 years ago

A set of weights includes a 5 lb barbell and 4 pairs of weight plates. Each pair of

Zina [86]

Answer:

The answer to this question would be B:

Based on the question, since the weight of the weight plates are 20 lbs, this would be represented by the 20x in the function. As well, the 5 lb barbell would be represented by the 5 in the function. The range of the function is determined by the amount of weight plates are added. So if I added one weight plate the equation would equal, f(x) = 20(1) + 5 = 25. This continues on the more and more weight plates you add.

Hope this reached you well :)

Step-by-step explanation:

20 = weight of the weight plates

x = amount of weight plates.

5 = weight of the barbell

f(x) = 20(0) + 5 = 5

f(x) = 20(1) + 5 = 25

f(x) = 20(2) + 5 = 45

f(x) = 20(3) + 5 = 65

f(x) = 20(4) + 5 = 85

5 0

3 years ago