The life expectancy in the US is 75 with a standard deviation of 7 years. A random sample of 49 individuals is selected. What is
the probability that the same mean will be larger than 77 years?
1 answer:
Answer:
0.02275
Step-by-step explanation:
We use this z score formula to solve for this question
z-score is is z = (x-μ)/σ/√n
where x is the raw score
μ is the population mean
σ is the population standard deviation
From the above question,
x = 77
μ = 75
σ = 7
number of samples = 49
Hence, the z score = 77 - 75/ (7/√49)
= 2/(7/7)
= 2/1
= 2
Hence, the z score = 2
Using the z table to find probability
P(x<77) = 0.97725
P(x>77) = 1 - P(x<77)
= 1 - 0.97725
= 0.02275
Therefore, the probability that the same mean will be larger than 77 years
is 0.02275
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Answer:
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Step-by-step explanation:
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Answer:
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