Answer:
200 ml
Step-by-step explanation:
It's proportions basically.
frst off, 2% of 100 ml is 2 ml, so the 100 ml solution has 2 ml of Minoxidil.
Eventually we want 6/100 to be the porportion. so the total is going to be 100 (from the initial 100 ml) plus however much is needed x. And we want the amount of Minoxidil to be 2 + 8 percent of x. so this gets us the equation
6/100 = (2 + .08x)/(100+x) Then we solve
(100 + x) 6/100 = 2 + .08x
(100 + x) 6 = 200 + 8x
600 + 6x = 200 + 8x
400 = 2x
x = 200
so they should add 200 ml
You can check too. there is 100 + 200 ml of solution total and 2 + 16 ml of Minoxidil so that's 18/300 = 6/100
Solve for X on both equations
2x - 2 < -12
Add two on both sides
2x < -10
Divide by two on both sides
2 < -5
2x + 3 > 7
Subtract three on both sides
2x > 4
Divide by two on both sides
x > 2
A. x < -5 or x > 2
Slope intercept form is: y = mx + b
Isolate the y. First subtract 10x from both sides
10x (-10x) + 2y = 8 (-10x)
2y = -10x + 8
Isolate the y. Divide 2 from both sides and <em>all</em> terms.
(2y)/2 = (-10x + 8)/2
y = -5x + 4
y = -5x + 4 is your slope intercept form answer.
hope this helps
Let the angle be x and it's complement be c.
Then, x = c + 88 and x + c = 90
Substitute the first equation in the second.
(c+88) + c = 90
2c+88 = 90
2c = 2
c =1
Compliment = 1
Angle = 89
Answer:
The 95% confidence interval for the true mean cholesterol content, μ, of all such eggs is between 226.01 and 233.99 milligrams.
Step-by-step explanation:
We have that to find our 
level, that is the subtraction of 1 by the confidence interval divided by 2. So:
Now, we have to find z in the Ztable as such z has a pvalue of 
.
So it is z with a pvalue of 
, so 
Now, find M as such
In which 
is the standard deviation of the population and n is the size of the sample.
The lower end of the interval is the sample mean subtracted by M. So it is 230 - 3.99 = 226.01
The upper end of the interval is the sample mean added to M. So it is 230 + 3.99 = 233.99.
The 95% confidence interval for the true mean cholesterol content, μ, of all such eggs is between 226.01 and 233.99 milligrams.
