y = -5x + 24
y = 4x - 21
Since both of these equations are equal to Y, theyre equal to each other.
So we can make an equation with y = -5x + 24 in one side and y = 4x - 21 on the other.
-5x + 24 = 4x - 21
Now in order to get the value of x we need to isolate it in one side of the equation. We can do this by subtracting 24 from both sides of the equation:
-5x + 24 - 24 = 4x - 21 - 24
-5x = 4x - 45
Now we subtract 4x from both sides so the 4x shift to the other side
-5x - 4x = 4x - 4x - 45
-9x = -45
Finally divide both sides by -9 so x is by itself
(-9)÷(-9x) = -(45)÷(-9)
x = 5
Since we did all of this to BOTH sides of the equation, both sides are still equal to each other and the equation still is true.
Now apply x = 5 to either of the initial equations to find the value of Y
y = -5x + 24 or y = 4x - 21
(I'll do both but u only need one)
y = -5(5) + 24
y = -25 + 24
y = -1
y = 4(5) - 21
y = 20 - 21
y = -1
Either way, X is 5 and Y is -1
Answer (5, -1)
I'll solve 21, and you then should be able to solve the rest on your own!
Since ADC is 135, that means that that whole angle is 135 degrees. In addition, since angles ADB and BDC add up to ADC, we get ADB+BDC=ADC=135=11x+9+7x=18x+9. Subtracting 9 from both sides, we get 126=18x. Dividing both sides by 18, we get x=7. Plugging that into 11x+9=BDC, we get 11*7+9=77+9=86
Answer:
51
Step-by-step explanation:
67 minus 16 equals 51
Answer:
2. The answer should be the last one.
3. The answer should be the first three.
Step-by-step explanation:
<u>Question 2</u>
KE = (1/2)mv²
2KE = mv²
v² = 2KE/m
v = ±√(2KE/m)
Therefore the answer should be the last one.
<u>Question 3</u>
b^(1/2) * b^(5/2)
Remember that the <u><em>product rule</em></u> states that b^x * b^y = b^(x+y)
So this means b^(1/2) * b^(5/2) = b^(1/2+5/2) = b^(6/2) = b^3
Also remember that the <u><em>power rule</em></u> states that √b = b^(1/2)
so this means b^(6/2) can also be written as (√b)^6
Therefore the answer should be the first three.
<em>If you want to double check all of your answers, just replace b with a number (for example, 2), and plug all of the choices into the calculator. Just </em><u><em>make sure</em></u><em> you are </em><u><em>very careful</em></u><em> when typing into the calculator.</em>
