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ArbitrLikvidat [17]
4 years ago
6

Mr. Smith ate a snack with 80.79 total calories. If the chips he ate were 43.39 calories, how

Mathematics
1 answer:
Paul [167]4 years ago
4 0

Answer:

37.40 calories

Hope this helps :)

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I need help with this 1 problem on my homework
Andru [333]

Step-by-step explanation:

10-5y=3x

1. add 10 to both sides

-5y=3x+10

2. divide everything by -5

y=-3/5x-2

3. your point would start at -2 on the y axis and you would go down 3 and over 5 to get to the next point

4 0
3 years ago
Which function is the inverse of f(x) = 2x + 3 ?<br> Help
bearhunter [10]

Answer:

The inverse is 1/2x -3/2

Step-by-step explanation:

y =2x+3

Exchange x and y

x = 2y+3

Solve for y, subtracting 3 from each side

x-3 = 2y+3-3

x-3 =2y

Divide each side by 2

(x-3)/2 = 2y/2

1/2x - 3/2 =y

The inverse is 1/2x -3/2

7 0
3 years ago
Read 2 more answers
1) A group of 35 people are going to run a
Lemur [1.5K]

Theres nothing we can do to hhelp u bruh

4 0
3 years ago
Population of Jacksonville was 3810 and 2010 and is growing at an annual rate of 3.5% if the growth rate continues what will the
grin007 [14]

Answer:

FV= 5,958.67 = 5,959

Step-by-step explanation:

Giving the following information:

Current population (Present Value)= 3,810

Growth rate (g)= 3.5% annual

Number of periods (n)= 13 years

<u>To calculate the future number of people (FV), we need to use the following formula:</u>

FV= PV*(1+i)^n

FV= 3,810*(1.035^13)

FV= 5,958.67 = 5,959

4 0
3 years ago
Insert geometric means in each geometric sequence.
Digiron [165]

Answer:

\underline{192}, 24, \underline{3}, \underline{\dfrac{3}{8}}, \dfrac{3}{64}

\underline{\dfrac{1}8}, \dfrac{1}{4}, \dfrac{1}{2}, \underline{1}

81, \underline{27, 9, 3, 1},\dfrac{1}{3}

Step-by-step explanation:

Given the Geometric sequences:

1. ___, 24, ___, ___, 3/64

2. ___, 1/4, 1/2, ___

3. 81, ___, ___, ___, ___, 1/3

To find:

The values in the blanks of the given geometric sequences.

Solution:

First of all, let us learn about the n^{th} term of a geometric sequence.

a_n=ar^{n-1}

Where a is the first term and

r is the common ratio by which each term varies from the previous term.

Considering the first sequence, we are given the second and fifth terms of the sequences.

Applying the above formula:

ar = 24\\ar^4 = \dfrac{3}{64}

Solving the above equation:

r = \dfrac{1}{8}

Therefore, the sequence is:

\underline{192}, 24, \underline{3}, \underline{\dfrac{3}{8}}, \dfrac{3}{64}

Considering the second given sequence:

ar = \dfrac{1}{4}\\ar^2 = \dfrac{1}{2}\\\text{Solving the above equations}, r = 2

Therefore, the sequence is:

\underline{\dfrac{1}8}, \dfrac{1}{4}, \dfrac{1}{2}, \underline{1}

Considering the third sequence:

a = 81\\ar^5=\dfrac{1}{3}\\\Rightarrow r = 3

Therefore, the sequence is:

81, \underline{27, 9, 3, 1},\dfrac{1}{3}

5 0
3 years ago
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