Equation of the perpendicular
y= 2x+6
slope of the perpendicular = 2
slope of the req. line = -1/2
equation of the req. line
y - y1 = m(x - x1)
y - 2 = -1/2(x + 4)
2(y - 2) = -1(x + 4)
2y - 4 = -x - 4
2y = -x
y = (-1/2)x
this is your req. equation of line.
You are asked to do this problem by graphing, which would be hard to do over the Internet unless you can do your drawing on paper and share the resulting image by uploading it to Brainly.
If this were homework or a test, you'd get full credit only if you follow the directions given.
If <span>The points(0,2) and (4,-10) lie on the same line, their slope is m = (2+10)/(-4), or m =-3. Thus, the equation of this line is y-2 = -3x, or y = -3x + 2.
If </span><span>points (-5,-3) and (2,11) lie on another line, the slope of this line is:
m = 14/7 = 2. Thus, the equation of the line is y-11 = 2(x-2), or y = 11+2x -4, or y = 2x + 7.
Where do the 2 lines intersect? Set the 2 equations equal to one another and solve for x:
</span>y = -3x + 2 = y = 2x + 7. Then 5x = 5, and x=1.
Subst. 1 for x in y = 2x + 7, we get y = 2(1) + 7 = 9.
That results in the point of intersection (2,9).
Doing this problem by graphing, on a calculator, produces a different result: (-1,5), which matches D.
I'd suggest you find and graph both lines yourself to verify this. If you want, see whether you can find the mistake in my calculations.
Answer:
Exponential growth
Step-by-step explanation:
We can solve this differential equation by the separation of variables method.
We have that:
So
Integrating both sides
In which K is the value of y when t = 0.
We apply the exponential to both sides, so:
This is our exponential equation. Since the power of e is a positive value, the function represents exponential growth.
3x^2 * 4x^3 = 12x^5
Answer is degree 5
